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Rom4ik [11]
2 years ago
10

What is the equation of this graphed line?

Mathematics
2 answers:
GrogVix [38]2 years ago
6 0
2,1 Correct 37$44634636444+64/+7$;+8$’codk odnicurn jfncurncjeuc
Liula [17]2 years ago
5 0

Answer:

2,1

Step-by-step explanation:

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Ralph is an electrician. He charges an initial fee of $37.50, plus $25 per hour. If Ralph earned $187.50 on a job, how long did
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Answer:

(x+3, y+2)

Step-by-step explanation:

choose a letter: let's use points A and A'

A: (-3, 3)

A': (0, 5)

the rule would be (x+3, y+2) because (-3+3, 3+2) = (0,5)

Try it on another point:

B: (-4, 0)

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7 0
2 years ago
The newsstand at the corner of Manilla Avenue and GreenTree Rd. in GreenTree sells the daily edition of The Pittsburgh Press. Th
Pavlova-9 [17]

Answer:

1 - NORM.DIST(625, 600, 15 ,TRUE)

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In Excel:

We use the norm.dist command.

NORM.DIST(x, mean, standard_dev ,cumulative)

x is the tested value, mean and standard_dev are the mean and the standard deviation, while cumulative we use true to find a probability of a value lower than x, so for a value higher than x, we use:

1 - NORM.DIST(x, mean, standard_dev ,TRUE)

Mean of 600 copies and a standard deviation of 15 copies.

mean = 600, standard_dev = 15

You want to find the probability of selling more than 625 newspapers on any given day.

x = 625

What is the Excel Command

1 - NORM.DIST(625, 600, 15 ,TRUE)

6 0
3 years ago
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