Answer: Molarity of the solution is
and water is the solvent.
Explanation:
Given: Mass of solute = 26.8 g
Volume = 4.00 L
Now, moles of copper (II) chloride (molar mass = 134.45 g/mol) are calculated as follows.

Molarity is the number of moles of a substance divided by volume of solution in liter.
Therefore, molarity of given solution is calculated as follows.

Solvent is defined as a component which is present in higher amount in a solution. Generally, a solvent is present in liquid state but it can also be a solid or gas.
In the given solution, copper (II) chloride is dissolved in water so copper (II) chloride is the solute and water is the solvent.
Thus, we can conclude that molarity of the solution is
and water is the solvent.
<em>c</em> = 1.14 mol/L; <em>b</em> = 1.03 mol/kg
<em>Molar concentration
</em>
Assume you have 1 L solution.
Mass of solution = 1000 mL solution × (1.19 g solution/1 mL solution)
= 1190 g solution
Mass of NaHCO3 = 1190 g solution × (7.06 g NaHCO3/100 g solution)
= 84.01 g NaHCO3
Moles NaHCO3 = 84.01 g NaHCO3 × (1 mol NaHCO3/74.01 g NaHCO3)
= 1.14 mol NaHCO3
<em>c</em> = 1.14 mol/1 L = 1.14 mol/L
<em>Molal concentration</em>
Mass of water = 1190 g – 84.01 g = 1106 g = 1.106 kg
<em>b</em> = 1.14 mol/1.106 kg = 1.03 mol/kg
<h3>
Answer:</h3>
4.73 × 10^4 m
<h3>
Explanation:</h3>
From the question;
Frequency of the photon = 634 × 10^12 Hz
We are required to calculate the wavelength of the photon.
We need to know the relationship between wavelength and frequency of a wave.
The relationship between f and λ is given by;
c = fλ
Where c, is the speed of light, 2.998 × 10^8 m/s
Therefore, to get the wavelength we rearrange the formula such that;
λ = c ÷ f
= 2.998 × 10^8 m/s ÷ 634 × 10^12 Hz
= 4.73 × 10^-5 m
But we require wavelength in nm
1 M = 10^9 nm
Therefore;
Wavelength = 4.73 × 10^-5 m × 10^9 nm/m
= 4.73 × 10^4 m
Hence, the photon's wavelength is 4.73 × 10^4 m
Because there is a higher volume of heat in the iceberg. Heat enery is the amount of heat there is in a substance. it may be cold heat or warm heat
The leaf would be on top of the wave after two seconds just like it was positioned at 0 seconds. After 3 seconds the leaf should be positioned like it was at 1 second. The leaf is moving along with the wave.