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NNADVOKAT [17]
3 years ago
7

For each of the following sublevels, give the n and l values and the number of orbitals: (a) 5s; (b) 3p; (c) 4f

Chemistry
1 answer:
OverLord2011 [107]3 years ago
6 0

Answer:

(a) 5s. n = 5. Sublevel s, l = 0. Number of orbitals = 1

(b) 3p. n = 3. Sublevel p, l = 1. Number of orbitals = 3

(c) 4f. n =4. Sublevel f, l = 3. Number of orbitals = 7

Explanation:

The rules for electron quantum numbers are:

1. Shell number, 1 ≤ n

2. Sublevel number, 0 ≤ l ≤ n − 1

So,

(a) 5s. n = 5, shell number 5. Sublevel s, l = 0. Number of orbitals = 2l +1 = 1

(b) 3p. n = 3, shell number 3. Sublevel p, l = 1. Number of orbitals = 2l +1 = 3

(c) 4f. n =4, shell number 4. Sublevel f, l = 3. Number of orbitals =  2l +1 = 7

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3 years ago
Iodine chloride, ICl, can be made by the following reaction between iodine, I2, potassium iodate, KIO3, and hydrochloric acid.
Vadim26 [7]
The balanced chemical reaction is:

<span>2 I2 + KIO3 + 6 HCl ---------> 5 ICl + KCl + 3 H2O 
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6 0
3 years ago
Read 2 more answers
PLEASE HELP!!!
NNADVOKAT [17]

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4 0
3 years ago
5 points
Orlov [11]

Answer:

The correct option is (a).

Explanation:

We need to find the product of given numbers.

First number = 29.5

Second number = 240

Product of two numbers = 29.5 × 240

= \dfrac{295}{10}\times 240

Zeroes from numerator and denominator get cancelled.

So,

=295\times 24\\\\=7080

Hence, the correct option is (a).

7 0
3 years ago
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