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2 years ago

Use the table to work out the values of a, b, c and d PLEASE HELP!!!

Mathematics

1 answer:

Taya2010 [7]2 years ago

8 0

Answer:

a = 10, b = 5, c = 14, d = 25

Step-by-step explanation:

Plug in -2 for x ....

y = 2(-2)^2 + -2 + 4

y = 2(4) + 2

y = 10

Plug in -1 for x ....

y = 2(-1)^2 + -1 + 4

y = 2(1) + 3

y = 5

Plug in 2 for x ....

y = 2(2)^2 + 2 + 4

y = 2(4) + 6

y = 8 + 6

y = 14

Plug in 3 for x ....

y = 2(3)^2 + 3 + 4

y = 2(9) + 7

y = 18 + 7

y = 25

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4x − 5y = 25<br> Make a table of values. ASAP

Lerok [7]

Answer:

Given Below.

explanation:

$4x - 5y = 25$

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$y = \frac{4x- 25}{5}$

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2 years ago

The area of a circle is 2464cm2.calculate it's diameter to 2 significant figures<br>

tigry1 [53]

Answer:

Step-by-step explanation:

Answer:

The diameter of the circle is 56 cm.

Step-by-step explanation:

Given : The area of the circle is 2464 cm square.

To find : The diameter of the circle?

Solution :

The area of the circle is defined as

Where, A=2464 cm² is the area,

r is the radius

Substituting the values,

Radius of the circle is 28 cm.

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2 years ago

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Step-by-step explanation:

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3 years ago

Samples of skin experiencing desquamation are analyzed for both moisture and melanin content. The results from 100 skin samples

zheka24 [161]

Answer: a. 0.40 b. 0.23 c . 0.435 d . 0.25

Step-by-step explanation:

melanin content Total

high low

moisture high 13 10 23

content low 47 30 77

Total 60 40 <u> </u><u>100</u>

Let A denote the event that a sample has low melanin content, and let B denote the event that a sample has high moisture content.

a) Total skin samples has low melanin content = 10+30=40

P(A)= $\dfrac{40}{100}=0.40$

b) Total skin samples has high moisture content = 13+10=23

P(B) = $\dfrac{23}{100}=0.23$

c) A ∩ B = Total skin samples has both low melanin content and high moisture content =10

P(A ∩ B) = $\dfrac{10}{100}=0.10$

Using conditional probability formula , $P (A|B)=\dfrac{P(A\cap B)}{P(B)}$

$P (A|B)=\dfrac{0.10}{0.23}=0.434782608696\approx0.435$

d) $P (B|A)=\dfrac{P(A\cap B)}{P(A)}$

$P (B|A)=\dfrac{0.10}{0.40}=0.25$

8 0

3 years ago

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5 0

2 years ago