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IrinaK [193]
4 years ago
7

7.00×10−3 mol of HBrare dissolved in water to make 12.0 L of solution. What is the concentration of hydroxide ions, [OH-], in th

is solution?.
Chemistry
2 answers:
frosja888 [35]4 years ago
7 0
To find it in the best way is 
7.00×10^−3 mol of HBr / 18.0 L of solution.= 3.89 e-4 Molar HBr 

<span>3.89 e-4 Molar HBr releases 3.89 e-4 Molar H+ </span>

<span>the pH = - log of 3.89 e-4 Molar H+ </span>

<span>since [H+] [OH-] = 1 e-14 the Kof water </span>

<span>[OH-] = 1 e-14 / 3.89 e-4 = 2.57 e-11 </span>
so we concluded that 
<span>[OH-} = 2.57 X 10^-11 </span>
butalik [34]4 years ago
3 0
Molarity :

M = n / V

M = 7.00 x 10⁻³ / 12.0

= 0.000583 M  => H+

Kw = [ H+] x [OH-]

1 x 10⁻¹⁴ = 0.000583 x [ OH-]

[ OH-] = 1 x 10⁻¹⁴ / 0.000583

[OH-] = 1.71 x 10⁻¹¹

hope this helps!


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In terms of energy, how would you classify the following chemical reaction?
olga_2 [115]

1. Answer;

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Explanation;

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2. Answer;

Conserved

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Explanation;

-According to the law of conservation of energy, energy is neither created nor destroyed. Energy may change form during a chemical reaction. For example, energy may change form from chemical energy to heat energy when gas burns in a furnace. However, the exact amount of energy remains after the reaction as before, which is true for all chemical reactions.

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Explanation:

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How much calcium hypochlorite (65% strength) is needed to make 200 L of 2% hypochlorite solution? (Assume that a 1% solution is
g100num [7]

To solve this we use the equation,

 

M1V1 = M2V2

 

where M1 is the concentration of the stock solution, V1 is the volume of the stock solution, M2 is the concentration of the new solution and V2 is its volume.

 

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5 0
4 years ago
How many moles of fe2o3 will be produced from 18.0 g of fe assuming o2 is available in excess
Advocard [28]

Answer:

0.161moles

Explanation:

Given parameters:

Mass of Fe  = 18g

Oxygen gas is in excess

Unknown:

Number of moles of Fe₂O₃ produced  = ?

Solution:

To start with, let us write a chemically balanced equation before proceeding to understand the nuances of this problem.

              4Fe       +    3O₂       →          2Fe₂O₃

In the equation above above, 4 mole of iron combined with 3 moles of oxygen gas to  2 moles of Fe₂O₃.

In solving this problem, we can identify that Fe is the limiting reactant since we have been told oxygen gas is in excess. The suggests that the extent to which the product is formed and the reaction proceeds hinges on the amount of Fe we have.

It is best to work from the given, or known reactant to the unknown

The known in this scenario is the mass of Fe. Let us find the number of moles of this specie;

        Number of moles of Fe  = \frac{mass}{molar mass}

              Molar mass of Fe  = 56g/mol

      Number of moles  = \frac{18}{56}   = 0.32mol

Using this known number of moles of Fe, we can relate it to that of the unknown amount of the product and obtain the number of moles.

           4 moles of Fe produced 2 moles of Fe₂O₃

         0.32 moles of Fe will produce \frac{0.32 x 2}{4}   =  0.161moles

8 0
3 years ago
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