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3 years ago

Help on this question please?

Chemistry

1 answer:

il63 [147K]3 years ago

8 0

Answer:

Your answer would be A. The fireworks

Explanation:

The reason behind this is because fireworks do produce light and sound, but they weren't made to. They were made with no noise but now they are more spectacular and "Boom" in the air with beautiful light with colors.

I hope this helps you! If I am totally screwed up and wrong. please let me know in the comment section below! Have a great day, my friend!

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A train that is accelerating at 5m/s² down the tracks and crashes into a car. If the train weighs 20,000kg, how much force does

iragen [17]

Answer:

100,000 N

Explanation:

Force, F = mass, m × acceleration, a

⇒F = ma

m= 20, 000kg

a = 5m/s²

∴ F = 5 × 20,000 = 100,000N

3 0

3 years ago

Flourine is found to undergo 10% radioactivity decay in 366 minutes determine its halflife

yuradex [85]

Answer:

$\boxed{\text{2408 min}}$

Explanation:

The integrated rate law for radioactive decay is

$\ln\dfrac{N_{0}}{N_{t}} = kt$

1. Calculate the decay constant

$\begin{array}{rcl}\ln \dfrac{100}{90} & = & k \times 366\\\\1.054 & = & 366k\\\\k & = & \dfrac{1.054 }{366}\\\\k & = & 2.879 \times 10^{-4} \text{ min}^{-1}\\\end{array}\\\\$

2. Calculate the half-life

$t_{\frac{1}{2}} = \dfrac{\ln2}{k}\\\\t_{\frac{1}{2}} = \dfrac{\ln2}{2.879 \times 10^{-4} \text{ min}^{-1}} = \text{2408 min}\\\\\text{The half-life for decay is } \boxed{\textbf{2408 min}}$

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3 years ago

Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills a 500.

yaroslaw [1]

Answer:

12. is the pressure equilibrium constant for the decomposition of ammonia at the final temperature of the mixture.

Explanation:

$2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g)$

initially

3.0 atm 0 0

At equilibrium

(3.0-2p) p 3p

Equilibrium partial pressure of nitrogen gas = p = 0.90 atm

The expression of a pressure equilibrium constant will be given by :

$K_p=\frac{p_{N_2}\times (p_{H_2})^3}{(p_{NH_3})^2}$

$K_p=\frac{p\times (3p)^3}{(3.0-2p)^2}$

$=\frac{0.90 atm\times (3\times 0.90 atm)^3}{(3.0-2\times 0.90 atm)^2}$

$K_p=12.30\approx 12.$

12. is the pressure equilibrium constant for the decomposition of ammonia at the final temperature of the mixture.

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3 years ago

Im about to take first year chemistry for engineering. Should i review or will this be done in class? If yes what are some conce

sashaice [31]

You should always study. you can be above your class. thats what i do.. search google for ur course. they can tell u some key points for it. u should even study what you know and want to know as well.

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3 years ago