I got that pH=3.65 using the fact that Ka=[H⁺][A⁻]/[HA] at equilibrium. In the ice table, I stands for initial, C stands for change, and E stands for equilibrium.
I hope this helps. Let me know if anything is unclear.
Answer:
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Answer:
The volume is 310 L
Explanation:
We use the ideal gas formula, with the constant R = 0.082 l atm / K mol. The STP conditions are 1 atm pressure and 273 K temperature. Solve for the formula, V (volume):
PV= nRT ---> V= (nRT)/P
V=( 14 mol x 0,082 l atm /K mol x 273 K)/ 1 atm
<em>V= 313,404 L</em>
Answer:
pH ( potential Hydrogen ) is a negative logarithm of molar concentration of hydrogen ions.
![pH = - log[H {}^{ + } ]](https://tex.z-dn.net/?f=pH%20%3D%20%20-%20%20log%5BH%20%7B%7D%5E%7B%20%2B%20%7D%20%5D)
therefore:

Answer:
- <u><em>You should expect that the ionic bond in LiBr is stronger than the bond in KBr.</em></u>
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Explanation:
The<em> ionic bonds</em> are formed by the electrostatic attraction between the ions, cations and anions.
In KBr the cation is K⁺ and the anion is Br⁻.
In LiBr the cation is Li⁺ and the anion is Br⁻.
You must expect that the bond strength depends mainly on the charges present on each ion and the distance between them.
Nevertheless, the effect of the distance between the radius dominate the trendency of the bond strength, which makes that the ionic strength trend be related to the ionic radius trend.
Lithium is a smaller ion than Potassium (both are in the same group and Lithium is above Potassium).
Thus, you should expect that the Li ion is closer to the Br ion than what the K ion is to the Br ion and expect that the bond between a Li ion and the Br ion be stronger than the bond between the K ion and the Br ion.