Answer: provided in the explanation section
Explanation:
Given that:
Assume D(k) =║ true it is [1 : : : k] is valid sequence words or false otherwise
now the sub problem s[1 : : : k] is a valid sequence of words IFF s[1 : : : 1] is a valid sequence of words and s[ 1 + 1 : : : k] is valid word.
So, from here we have that D(k) is given by the following recorance relation:
D(k) = ║ false maximum (d[l]∧DICT(s[1 + 1 : : : k]) otherwise
Algorithm:
Valid sentence (s,k)
D [1 : : : k] ∦ array of boolean variable.
for a ← 1 to m
do ;
d(0) ← false
for b ← 0 to a - j
for b ← 0 to a - j
do;
if D[b] ∧ DICT s([b + 1 : : : a])
d (a) ← True
(b). Algorithm Output
if D[k] = = True
stack = temp stack ∦stack is used to print the strings in order
c = k
while C > 0
stack push (s [w(c)] : : : C] // w(p) is the position in s[1 : : : k] of the valid world at // position c
P = W (p) - 1
output stack
= 0 =
cheers i hope this helps !!!
Answer:
Originally Answered: Will there ever be a band as big as the Beatles? No, there will never be a band as popular as the Beatles. For one thing they were exceptionally good in a time of great music in general.
Explanation:
please mark this answer as brainliest
Answer:
Option C: Numbers.
Explanation:
By default, rows within a spreadsheet are identified by Numbers i.e. 1,2,3,............
Total rows are 1048575 in one spreadsheet.
Answer:
The answer is "Option A".
Explanation:
- In the given C++ Language program on line 8 compile-time error will occur, because in the code the conditional statement is used. In if block, we check two conditions together, which is the number variable value is greater than equal to 0 and check less than equal to 100.
- In this condition statement, a AND operator is used that execute when both condition is true, but in the last condition, we do not define a variable name that, checks value. That's why the program will give an error on line 8.
