Answer:
Each unit cost $800
Step-by-step explanation:
Annual compensation = $48,000
Annual number of units sold = 2000
Commission on each item sold = 3%
Compensation for 2000 units = $48,000
Compensation for 1 unit = $48,000/2000 = $24
Cost of one unit = compensation for one unit ÷ commission on one unit = $24 ÷ 3% = $24 ÷ 0.03 = $800
(9,-5) times 2.5 is (22.5,-12.5)
The answer is (22.5,-12.5)
Hope this helps!
Answer:
option-C
Step-by-step explanation:
We are given
At 9:00 a.m., a wind speed of 20 miles per hour was recorded
So, initial wind speed =20 miles per hour
Each measurement showed an increase in wind speed of 3 miles per hour
The strongest wind was recorded at 4:00 p.m
so,
top wind speed = initial wind speed + ( total number of hours between 9:00 am and 4:00 pm)*(change in wind speed)
top wind speed = 20 mph+(16-9)*3

miles per hour
Since, change in wind speed and initial wind speed are constant
but the number of hours it took for the wind speed to reach its minimum for the day can be changed
so, most important variables is
the number of hours it took for the wind speed to reach its minimum for the day can be changed
Here is our profit as a function of # of posters
p(x) =-10x² + 200x - 250
Here is our price per poster, as a function of the # of posters:
pr(x) = 20 - x
Since we want to find the optimum price and # of posters, let's plug our price function into our profit function, to find the optimum x, and then use that to find the optimum price:
p(x) = -10 (20-x)² + 200 (20 - x) - 250
p(x) = -10 (400 -40x + x²) + 4000 - 200x - 250
Take a look at our profit function. It is a normal trinomial square, with a negative sign on the squared term. This means the curve is a downward facing parabola, so our profit maximum will be the top of the curve.
By taking the derivative, we can find where p'(x) = 0 (where the slope of p(x) equals 0), to see where the top of profit function is.
p(x) = -4000 +400x -10x² + 4000 -200x -250
p'(x) = 400 - 20x -200
0 = 200 - 20x
20x = 200
x = 10
p'(x) = 0 at x=10. This is the peak of our profit function. To find the price per poster, plug x=10 into our price function:
price = 20 - x
price = 10
Now plug x=10 into our original profit function in order to find our maximum profit:
<span>p(x)= -10x^2 +200x -250
p(x) = -10 (10)</span>² +200 (10) - 250
<span>p(x) = -1000 + 2000 - 250
p(x) = 750
Correct answer is C)</span>
Answer:
264
Step-by-step explanation:
well you could have just used a calculator!