Moles of Lithium phosphate : 0.495
<h3>Further explanation</h3>
Given
6 Li + Zn₃(PO₄)₂ ------- > 2 Li₃PO₄ + 3 Zn
Required
Moles of Lithium phosphate
Solution
moles of Zinc(Ar=65,38 g/mol) :
= mass : Ar
= 48.6 : 65.38
= 0.743
From equation, mol ratio of Zn : Li₃PO₄ = 3 : 2, so mol Li₃PO₄ :
= 2/3 x mol Zn
= 2/3 x 0.743
= 0.495
This is the answer to question 19. If it’s not clear, send me a message.
Answer:
76.03 °C.
Explanation:
Equation:
C2H5OH(l) --> C2H5OH(g)
ΔHvaporization = ΔH(products) - ΔH (reactants)
= (-235.1 kJ/mol) - (-277.7 kK/mol)
= 42.6 kJ/mol.
ΔSvaporization = ΔS(products) - ΔS(reactants)
= 282.6 J/K.mol - 160.6 J/K.mol
= 122 J/K.mol
= 0.122 kJ/K.mol
Using gibbs free energy equation,
ΔG = ΔH - TΔS
ΔG = 0,
T = ΔH/ΔS
T = 42.6/0.122
= 349.18 K.
Coverting Kelvin to °C,
= 349.18 - 273.15
= 76.03 °C.
Answer:
The 95% confidence level is
Explanation:
If we can apply the central limit theorem, we can approximate this distribution to a normal distribution.
The confidence level (for n=1) is defined as
For a 95% confidence interval, according to the normal distribution, z=1.96.
Then we have:
Answer:
11 protons and 11 electrons.
Explanation:
Na is a neutral element and element number 11.
This means that it has 11 protons and 11 electrons.
In order to create an isotope, you would add or get rid of neutrons to get different mass numbers but the same element. The number of protons and electrons would remain the same.
