Answer:
Mass of 205 mL of the liquid is 164 g
Explanation:
We know, 
Here density of liquid is 0.798 g/mL and volume of liquid is 205 mL
So, mass of liquid = 
= 
= 164 g
hence mass of 205 mL of the liquid is 164 g.
Answer is C.) G<span>oes from extremely cold to extremely hot during a lunar day </span>
The reason is because the temperatures on the moon<span> are very hot in the daytime, about 100 degrees C. At night, the </span>lunar <span>surface gets very cold, as cold as minus 173 degrees C. This wide variation is because Earth's </span>moon has no atmosphere to hold in heat at night or prevent the surface from getting so hot during the day.
D would be your best bet because evaporation occurs when water is heated, it then vibrates and then magic!
Answer:
5.5 L
Explanation:
Step 1: Given data
- Initial volume (V₁): 6.5 L
- Initial pressure (P₁): 840 mmHg
- Initial temperature (T₁): 84 °C
- Final pressure (P₂): 760 mmHg (standard pressure)
- Final temperature (T₂): 273.15 K (standard temperature)
Step 2: Convert T₁ to Kelvin
We will use the following expression.
K = °C + 273.15
K = 84 °C + 273.15 = 357 K
Step 3: Calculate the final volume of the gas
We will use the combined gas law.
P₁ × V₁ / T₁ = P₂ × V₂ / T₂
V₂ = P₁ × V₁ × T₂ / T₁ × P₂
V₂ = 840 mmHg × 6.5 L × 273.15 K / 357 K × 760 mmHg = 5.5 L
Answer:
C(s) + O2(g) 》CO2 (g)
Explanation:
to check CO2 is release mix the gas with quick lime you see colour is change