Answer:
R = 0.064 dm³ atm K⁻¹ mol⁻¹
Explanation:
Answer:
Explanation:
Data Given:
volume of gas V = 8.8 dm³
no. of mole of gas (n) = 1 mole
Pressure P = 259,392.00 Pa
Convert Pascal (Pa) to atm (atmospheric pressure)
As
101,325 Pascals = 1 atm
So,
259,392.00 Pa = 2 atm
Then Pressure (P) = 2 atm
Temperature T = 2.00 °C
change the temperature from °C to K
As to convert °C to K the below formula used
0°C + 273.15 = 273.15K
So, for 2 °C
2°C + 273.15 = 275.15 K
So,
Temperature T = 275.15 K
ideal gas constant = ?
formula used for Ideal gases
PV = nRT
as we have to find R of the gas:
we will rearrange the ideal gas equation as below:
R = PV / nT ........................................... (1)
Put value in equation (1)
R = 2atm x 8.8 dm³ / 1 mole x 275.15 K
R = 17.6 atm. dm³ / 275.15 mol. K
R = 0.064 dm³ atm K⁻¹ mol⁻¹
So the value of R is 0.064 dm³ atm K⁻¹ mol⁻¹
and the unit of R (ideal gas constant) is dm³ atm K⁻¹ mol⁻¹
