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solong [7]
2 years ago
6

If you are given an ideal gas with pressure (P) = 259,392.00 Pa and temperature (T) = 2.00 oC of 1 mole Argon gas in a volume of

8.8 dm3 , calculate R to the correct number of significant figures and units under given condition
Chemistry
1 answer:
3241004551 [841]2 years ago
7 0

Answer:

 R = 0.064 dm³ atm K⁻¹ mol⁻¹

Explanation:

Answer:

Explanation:

Data Given:

volume of gas V = 8.8 dm³

no. of mole of gas (n) = 1 mole

Pressure P = 259,392.00 Pa  

Convert Pascal (Pa) to atm (atmospheric pressure)

As

101,325 Pascals = 1 atm

So,

259,392.00 Pa  = 2 atm

Then Pressure (P) = 2 atm

Temperature T = 2.00 °C  

change the temperature from °C to K

As  to convert °C to K the below formula used

                   0°C + 273.15 = 273.15K

So, for 2 °C

                    2°C  + 273.15 =  275.15 K

So,

Temperature T  = 275.15 K

ideal gas constant = ?

formula used for Ideal gases

                            PV = nRT

as we have to find R of the gas:

we will rearrange the ideal gas equation as below:

R = PV / nT ........................................... (1)

Put value in equation (1)

                 R = 2atm x 8.8 dm³ / 1 mole x 275.15 K

                  R = 17.6 atm. dm³ / 275.15 mol. K

                  R = 0.064 dm³ atm K⁻¹ mol⁻¹

So the value of R is 0.064 dm³ atm K⁻¹ mol⁻¹

and the unit of R (ideal gas constant) is dm³ atm K⁻¹ mol⁻¹

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Hope this helps :)

Have a great day!
7 0
2 years ago
What is a physical change that could not easily be reversed?
mylen [45]

Answer:

the answer is number 1

Explanation:

because when you make toast you burn it you toast it and there is no way to undo that.

8 0
3 years ago
Which category does the ion PO43- belong to?
Katena32 [7]

Answer:

c polyatomic anion

Explanation:

8 0
2 years ago
You have a mixture that contains 0.380 moles of Ne(g), 0.250 moles of He(g), and 0.500 moles CH4(g) at 400 K and 6.25 atm. What
Bas_tet [7]

Answer:

1.38 atm

Explanation:

Partial pressure of a gas = total pressure × mole fraction of that gas.

Mole fraction of a gas is moles of a gas ÷ total moles of all gases.

4 0
2 years ago
Point How many grams of NaCl are present in 11.00 moles? ​
OlgaM077 [116]

Answer:

642.8g

Explanation:

NaCl has a molar mass of 58.44g/mol, which means one mole of NaCl has a mass of 58.44g.

11 moles of NaCl will have a mass of 642.8g.

11 mol NaCl x 58.44g = 642.8g

6 0
2 years ago
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