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ivanzaharov [21]
3 years ago
11

Which correctly lists the three agents that must be present for cementation to occur?

Chemistry
2 answers:
DaniilM [7]3 years ago
7 0

Answer:

water, minerals, sediment

Explanation:

bija089 [108]3 years ago
3 0
Water,minerals,sediment
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Rank the following 0.100 M solutions in order of increasing H3O+ concentration:
Inessa05 [86]

Answer:

HCN < HOCl < HF  

Explanation:

The larger the Kₐ value, the stronger the acid.

6.2 × 10⁻¹⁰ < 4.0 × 10⁻⁸ < 6.3 × 10⁻⁴

   HCN      <     HOCl    <      HF

 weakest       stronger    strongest

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3 years ago
What structure is found in some but not all plant cells
AlekseyPX
The chloroplasts i believe is the answer
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Which forces are intramolecular and which intermolecular?
AleksAgata [21]

Butter won't melt in a fridge because of intermolecular tensions. While the bonds inside of the fat molecules are unbroken, the attractions between the fat molecules are weaker.

What intermolecular forces are present in butter?

The intermolecular forces known as London dispersion forces are the weakest and are most prominent in hydrocarbons. Due to the fact that butter molecules are hydrocarbons, London dispersion forces do exist between them.

How do intermolecular forces affect melting?

More energy is required to stop the attraction between these molecules as the intermolecular forces become more powerful. Because of this, rising intermolecular forces are accompanied with rising melting points.

Which forces are intramolecular and which are intermolecular?

Intramolecular forces are those that hold atoms together within molecules. The forces that hold molecules together are known as intermolecular forces.

Learn more about intermolecular forces: brainly.com/question/9328418

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4 0
1 year ago
The rate constant for the second-order reaction: 2NOBr(g) → 2NO(g) + Br2(g) is 0.80/(M · s) at 10°C. Starting with a concentrati
a_sh-v [17]

Answer : The concentration of NOBr after 95 s is, 0.013 M

Explanation :

The integrated rate law equation for second order reaction follows:

k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)

where,

k = rate constant = 0.80M^{-1}s^{-1}

t = time taken  = 95 s

[A] = concentration of substance after time 't' = ?

[A]_o = Initial concentration = 0.86 M

Now put all the given values in above equation, we get:

0.80=\frac{1}{95}\left (\frac{1}{[A]}-\frac{1}{(0.86)}\right)

[A] = 0.013 M

Hence, the concentration of NOBr after 95 s is, 0.013 M

4 0
3 years ago
A mixture of gases A2 and B2 are introduced to a slender metal cylinder that has one end closed and the other fitted with a pist
REY [17]

Answer:

q < 0, w > 0, the sign of ΔE cannot be determined from the information given

Explanation:

Determination of sign of q

Temperature of the water bath before the reaction = 25 °C

Temperature of the water bath after the completion of the reaction = 28 °C

After the completion of the reaction, temperature of the water bath is increased that means heat is released during the reaction and flows out of the system.

If heat is absorbed by the system, then q is indicated by positive sign and if heat is released by the system, then q is indicated by negative sign.

As in the given case, heat is released by the system, so sign of q is negative, or q < 0

Determination of sign of w

After the completion of the reaction, piston moved downward, that means volume of the system decreases or compression occur. During the compression, work is done on the system.

if work is done on the system, sign of w is positive.

If work is done by the system, sign of w is negative.

In the given case, work is done on the system, therefore sign of w is positive, or w > 0

Determination of sign of ΔE

Relationship between ΔE, q and w is given by first law of thermodynamics:

ΔE = q + w

In this case, q is positive and w is negative, so the sign of ΔE depends of magnitude of q and w. As magnitude of w and q cannot be determined in this case, thus, the given information is insufficient for the determination of sign of ΔE.

So, among the given option, option c is correct.

q < 0, w > 0, the sign of ΔE cannot be determined from the information given

3 0
3 years ago
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