Answer:
5. (2,4) 6. (-1,6)
Step-by-step explanation:
The solution to multiple graphs is where the two graphs meet.
(-1,6) is the only point where both of the y values are the same.
keeping in mind that parallel lines have the same exact slope, hmmmm what's the slope of the line above anyway?

so we're really looking for the equation of a line whose slope is 1/3 and runs through (18,2)

Answer
A is the symbol for parallel lines AB and XY.
Explanation
B shows that line segment AB and XY are parallel, because there are no arrows, and line segments do not extend forever.
C shows that ray AB and XY are parallel, because there is one arrow, and rays only extend on one point.
Only A shows that line AB and XY are parallel. Lines extend forever, the A shows that AB and XY are parallel, since there are arrows in both directions above AB and XY.
Answer:
There is a 95% confidence that the true mean height of all male student at the large college is between the interval (63.5, 74.4).
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population mean is:

The (1 - α)% confidence interval for population parameter implies that there is a (1 - α) probability that the true value of the parameter is included in the interval.
Or, the (1 - α)% confidence interval for the parameter implies that there is (1 - α)% confidence or certainty that the true parameter value is contained in the interval.
The 95% confidence interval for the average height of male students at a large college is, (63.5 inches, 74.4 inches).
The 95% confidence interval for the average height of male students (63.5, 74.4) implies that, there is a 0.95 probability that the true mean height of all male student at the large college is between the interval (63.5, 74.4).
Or, there is a 95% confidence that the true mean height of all male student at the large college is between the interval (63.5, 74.4).
Distribute 2 and remove parentheses :
1/2x+8=3x-6
Multiply both sides of equation by 2:
x+16=6x-12
Move terms:
x+16-6x=-12
x-6x=-12-16
Collect like terms:
-5x=-28
Divide both sides:
x=28/5