Answer:
r=63
Step-by-step explanation:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
r/3-(21)=0 r
Simplify —
3
r
— - 21 = 0
3 2.1 Subtracting a whole from a fraction
Rewrite the whole as a fraction using 3 as the denominator :
21 21 • 3
21 = —— = ——————
1 3
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole
Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator
Answer:

Step-by-step explanation:
You only need two points on a line to find the equation for that line.
We are going to use 2 points that cross that line or at least come close to. You don't have to use the green points... just any point on the line will work. You might have to approximate a little.
I see ~(67.5,67.5) and ~(64,65).
Now once you have your points, we need to find the slope.
You may use
where
are points on the line.
Or you can line up the points vertically and subtract then put 2nd difference over 1st difference.
Like this:
( 64 , 65 )
-( 67.5, 67.5 )
--------------------
-3.5 -2.5
So the slope is -2.5/-3.5=2.5/3.5=25/35=5/7.
Now use point-slope form to find the equation:
where
is the slope and
is a point on the line.

Distribute:

Simplify:

Add 65 on both sides:

Simplify:

Answer:
5/9
Step-by-step explanation:
Answer:
The width of the rectangle is 14'8", and the length is 33'4"
Step-by-step explanation:
We're given two pieces of information:
The length is eight more than twice the width:

The perimeter is 96 feet:

We also need to apply one more piece of information that is not provided here, and that is the relationship between the perimeter of a rectangle, and it's length and width:

We can solve for w by plugging the other two values into the last:

Now we can find the length by plugging w into the first equation:

One third of a foot is four inches, so the width is 14'8" and the length is 33'4"
To make sure our answer is correct, we should plug those numbers back into the area equation and see if we're right:

So we know our answer's correct