I think it’s d because it’s like similar
Answer:
The value of
is 17-18x and
is -7-18x.
Step-by-step explanation:
It is given in the question functions f(x) as 3x+2 and g(x)=5-6x.
It is required to find
and
.
To find
, substitute g(x) for x in f(x) and simplify the expression.
To find
, substitute f(x) for x in g(x) and simplify the expression.
Step 1 of 2
Substitute g(x) for x in f(x) and simplify the expression.
![$$\begin{aligned}&(f \circ g)(x)=f(5-6 x) \\&(f \circ g)(x)=3(5-6 x)+2 \\&(f \circ g)(x)=15-18 x+2 \\&(f \circ g)(x)=17-18 x\end{aligned}$$](https://tex.z-dn.net/?f=%24%24%5Cbegin%7Baligned%7D%26%28f%20%5Ccirc%20g%29%28x%29%3Df%285-6%20x%29%20%5C%5C%26%28f%20%5Ccirc%20g%29%28x%29%3D3%285-6%20x%29%2B2%20%5C%5C%26%28f%20%5Ccirc%20g%29%28x%29%3D15-18%20x%2B2%20%5C%5C%26%28f%20%5Ccirc%20g%29%28x%29%3D17-18%20x%5Cend%7Baligned%7D%24%24)
Step 2 of 2
Substitute f(x) for x in g(x) and simplify the expression.
![$$\begin{aligned}&(g \circ f)(x)=g(3 x+2) \\&(g \circ f)(x)=5-6(3 x+2) \\&(g \circ f)(x)=5-18 x-12 \\&(g \circ f)(x)=-7-18 x\end{aligned}$$](https://tex.z-dn.net/?f=%24%24%5Cbegin%7Baligned%7D%26%28g%20%5Ccirc%20f%29%28x%29%3Dg%283%20x%2B2%29%20%5C%5C%26%28g%20%5Ccirc%20f%29%28x%29%3D5-6%283%20x%2B2%29%20%5C%5C%26%28g%20%5Ccirc%20f%29%28x%29%3D5-18%20x-12%20%5C%5C%26%28g%20%5Ccirc%20f%29%28x%29%3D-7-18%20x%5Cend%7Baligned%7D%24%24)
Answer:
Lee has 19 nickels and 8 dimes
Step-by-step explanation:
hello, I think I can help you with this
Step 1
Let
value of a nickel=$0.05
value of a dime=$0.10
number of nickels=N
number of nickels=D
According to the question data Lee has $1.75 in dimes and nickels.
0.05N+0.1D=1.75,equation(1)
also, the number of nickels is 11 more than the number of dimes.mathematical speaking
N=11+D,equation(2)
Step 2
replace N from equation (2) into equation (1)
0.05N+0.1D=1.75
0.05(11+D)+0.1D=1.75
Now, solve for D
0.55+0.05D+0.1D=1.75
0.15D=1.75-0.55
D=1.2/0.15
D=8
Step 3
replace the value of D into equation(2) to obtain N
N=11+8
N=11+8
N=19
Hence, Lee has 19 nickels and 8 dimes
Have a great day.
ΔABC and ΔCBD are similar. Therefore we have the proportion:
![\dfrac{AB}{BC}=\dfrac{BC}{BD}\\\\AB=6;\ BC=x;\ BD=2](https://tex.z-dn.net/?f=%5Cdfrac%7BAB%7D%7BBC%7D%3D%5Cdfrac%7BBC%7D%7BBD%7D%5C%5C%5C%5CAB%3D6%3B%5C%20BC%3Dx%3B%5C%20BD%3D2)
Substitute:
<em>cross multiply</em>
![(x)(x)=(6)(2)\\\\x^2=12\to x=\sqrt{12}\\\\x=\sqrt{4\cdot3}\\\\x=\sqrt4\cdot\sqrt3\\\\\boxed{x=2\sqrt3}](https://tex.z-dn.net/?f=%28x%29%28x%29%3D%286%29%282%29%5C%5C%5C%5Cx%5E2%3D12%5Cto%20x%3D%5Csqrt%7B12%7D%5C%5C%5C%5Cx%3D%5Csqrt%7B4%5Ccdot3%7D%5C%5C%5C%5Cx%3D%5Csqrt4%5Ccdot%5Csqrt3%5C%5C%5C%5C%5Cboxed%7Bx%3D2%5Csqrt3%7D)