Solution B (17% alcohol) = x ml
Solution A (13% alcohol) = (x-100) ml
0.17x ml alcohol in Solution B
0.13(x-100) ml alcohol in Solution A
0.17x + 0.13(x-100) = 347
0.17x+0.13x-13=347
0.3x = 360
x=360/0.3=3600/3=1200 ml solution B
Wave A has the shorter wavelength due too the fact that the shorter the wavelength the higher the frequency as they have an inverse relationship.
Answer:
mole fraction hexane 0.64
Explanation:
We know from Raoult's law of partial pressures that for a binary mixture, the vapor pressure above solution is the sum of the partial pressures of each gas:
P total = P(A) + P(B)
Also the partial pressure of a component is the product of its mole fraction , X, times its pure vapor pressure:
Ptotal = X (A)Pº(A) + X (B)Pº(B)
Since for solution of two components the mole fractions add to one, we now have all the information required to compute the answer.
250 torr = X(hexane)151 torr + ( 1 - X(hexane) )425 torr
250 = 151X(hexane) + 425 - 425 X(hexane)
274 X(hexane) = 175
X(hexane) = 1 -0.6 = 0.64
Answer:
0.12 M hydrofluoric acid + 0.17 M potassium fluoride
Explanation:
To make a buffer, you must to have an aqueous mixture of a weak acid and its conjugate base or vice versa.
Knowing that:
0.32 M calcium chloride + 0.27 M sodium chloride: <em>is not a good buffer system </em>because CaCl₂ and NaCl are both salts.
0.35 M ammonia + 0.36 M calcium hydroxide <em>is not a good buffer system </em>because ammonia is a weak base but calcium hydroxide is a strong base
0.19 M barium hydroxide + 0.28 M barium chloride <em>is not a good buffer system </em>because Ba(OH)₂ is a strong base.
0.12 M hydrofluoric acid + 0.17 M potassium fluoride <em>is a good buffer system </em>because HF is a weak acid and KF (F⁻ in aqueous medium), is its conjugate base
0.20 M hydrobromic acid + 0.22 M sodium bromide <em>is not a good buffer system </em>because HBr is a strong acid.
Answer:
0.15 (M) of NaCl
Explanation:
An isotonic solution is defined as the solution having the same osmolarity, or the same solute concentration, as the another solution. If the two solutions are to be separated by any semipermeable membrane, then water will start flowing in equal parts from each solution and also into the other.
In the context, since it is given that the red blood cells exerts the same osmotic pressure as a 0.15 (M) of NaCl solution.
Thus, 0.15 (M) of NaCl is a isotonic solution.
