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Svetradugi [14.3K]
3 years ago
10

"How many grams of CaCl2 would be dissolved in 1.0 L of a 0.10 M solution of CaCl2? "

Chemistry
1 answer:
lukranit [14]3 years ago
6 0

Answer:

2365 g

Explanation:

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Read 2 more answers
For double-helix formation, DG can be measured to be 2 54 kJ mol 1 ( 2 13 kcal mol 1 ) at pH 7.0 in 1 M NaCl at 25 8C (298 K). T
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Answer:

ΔS = -661.0J/mol is the entropy change for the system

ΔS = -842J/mol.K is the entropy change for the surroundings

Explanation:

From the relationship between ΔG, T, ΔH and ΔS,

Mathematically, ΔG = ΔH - TΔS

TΔS = ΔH - ΔS

ΔS = ΔH - ΔS / T

but ΔG = -54 kJ/mol, ΔH = -251 kJ/mol and T = 25 °C (298 K)

plugging into the equation,

ΔS = -251 kJ/mol - ( -54 kJ/mol) / 298

ΔS  = -0.6610KJ/mol or in J.mol

ΔS = -661.0J/mol is the entropy change for the system

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  • ΔS  = -251 kJ/mol / 298K
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