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2 years ago

$75 to $25 show your work

Mathematics

1 answer:

Vilka [71]2 years ago

4 0

Answer:

decrease

Step-by-step explanation:

the percent change measures FROM the first value. A change from 50 to 75 is a change of 50% (25 is the difference between the two numbers, and 25 is 50% of 50). A change from 75 to 50 is a change of -33.3% (25 is still the difference between the two. 25 is 33.3% of 75

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Caroline has some dimes and some quarters. She has a maximum of 15 coins worth at least $2.85 combined. If Caroline has 3 dimes,

gayaneshka [121]

Answer:

11, 12.

Step-by-step explanation:

Let q represent number of quarters.

We have been given that Caroline has a maximum of 15 coins worth at least $2.85 combined. We are also told that Caroline has 3 dimes. This means that total coins are less than or equal to 15.

We can represent this information in an inequality as:

$q+3\leq 15...(1)$

We are also told that the coins worth at least $2.85 combined. This means that the worth of all coins is greater than or equal to 2.85.

We know that each dime is worth $0.10 and each quarter is worth $0.25.

$0.25q+3(0.10)\geq 2.85...(2)$

Now, let us solve our system of inequalities.

From 1st inequality, we will get:

$q+3-3\leq 15-3$

$q\leq 12$

From 2nd inequality, we will get:

$0.25q+0.30\geq 2.85$

$0.25q+0.30-0.30\geq 2.85-0.30$

$0.25q\geq 2.55$

$\frac{0.25q}{0.25}\geq \frac{2.55}{0.25}$

$q\geq 10.2$

Upon combining our both inequalities, we will get:

$10.2\leq q\leq 12$

This means that numbers of quarters would be greater than or equal to 10.2 and less than or equal to 12.

Since we cannot have 0.2 of a coin, therefore, Caroline could have 11 or 12 quarters.

6 0

2 years ago

3 folders cost $2.91.<br> Which equation would help determine the cost of 2 folders?

-Dominant- [34]

Answer:

194

Step-by-step explanation:

2/3X=291

x=194

8 0

2 years ago

How do I solve this

nexus9112 [7]

the formula is

$measure \: of arc/360× \: \pi {r}^{2}$

7 0

3 years ago

Let a, b, c and x elements in the group G. In each of the following solve for x in terms of a, b, and c.

Nezavi [6.7K]

Answer:

$x=c.a^{-1}.b^{-1}$

Step-by-step explanation:

Given equation,

$axb = c-----(1)$

$(axb) ( a^{-1}.b^{-1} ) = c.(a^{-1}b{-1})$

$(xb)(a)(a^{-1}.b^{-1} ) = c.(a^{-1}b{-1})$ ( commutative law of multiplication )

$(xb)(a.a^{-1}).b^{-1} = c.a^{-1}b{-1}$ ( Associative property )

$(xb).e.b^{-1} = c.a^{-1}b{-1}$

$(xb).b^{-1}=c.a^{-1}.b^{-1}$ ( identity property )

$x.(b.b^{-1})=c.a^{-1}.b^{-1}$ ( Associative property )

$x.e=c.a^{-1}.b^{-1}$

$x=c.a^{-1}.b^{-1}$ ( identity property )

5 0

3 years ago

The mode interval in a histogram is the interval that has the highest frequency.

raketka [301]

This is true.

When we're talking about the mode, we're usually talking about the number which has the highest frequency in a given set of numbers. For example, out of the numbers:

1 2 3 4 5 6 5 4 5 5 5

5 will be the mode.

4 0

3 years ago