Answer:
w is the variable
Step-by-step explanation:
the letters you see next to the numbers the variable.
Answer:
B. ( –3, –4)
C. ( 4, 17 )
Step-by-step explanation:
Function: y = 3x + 5
Using method of elimination
A. (2, –1)
x = 2, y = -1
-1 = 3 (2) + 5
-1 ≠ 11
This option is incorrect!
B. ( –3, –4)
x = -3, y = -4
-4 = 3 (-3) + 5
-4 = - 9 + 5
-4 = -4
This option is correct!
C. ( 4, 17 )
x = 4, y = 17
17 = 3 (4) + 5
17 = 12 + 5
17 = 17
This option is correct!
D. ( 3, 8 )
x = 3, y = 8
8 = 3 (3) + 5
8 = 9 + 5
8 = 14
This option is incorrect!
The complete question is: Henry knows that the circumference of a circle is
18π inches. What is the area of the circle?
Solution:Circumference (C) of the circle can be written as:

Using this value of radius, we can find the Area(A) of the circle.
Therefore, area of the circle having a circumference of 18π inches will be 81π inches²
The answer is x2<span> – 2</span>x<span> – 9 and that is option C</span>
Let’s find some exact values using some well-known triangles. Then we’ll use these exact values to answer the above challenges.
sin 45<span>°: </span>You may recall that an isosceles right triangle with sides of 1 and with hypotenuse of square root of 2 will give you the sine of 45 degrees as half the square root of 2.
sin 30° and sin 60<span>°: </span>An equilateral triangle has all angles measuring 60 degrees and all three sides are equal. For convenience, we choose each side to be length 2. When you bisect an angle, you get 30 degrees and the side opposite is 1/2 of 2, which gives you 1. Using that right triangle, you get exact answers for sine of 30°, and sin 60° which are 1/2 and the square root of 3 over 2 respectively.
Now using the formula for the sine of the sum of 2 angles,
sin(A + B) = sin A cos<span> B</span> + cos A sin B,
we can find the sine of (45° + 30°) to give sine of 75 degrees.
We now find the sine of 36°, by first finding the cos of 36°.
<span>The cosine of 36 degrees can be calculated by using a pentagon.</span>
<span>that is as much as i know about that.</span>