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vovikov84 [41]
2 years ago
5

Which equation represents a line that passes through (-9, -3) and has a slope of -6? - = y-9 = -6(x-3) y + 9 = -6(x + 3) y-3 = -

6(x-9) O y + 3 = -6(x + 9) = x ​
Mathematics
1 answer:
kupik [55]2 years ago
4 0

Answer:

(y+3)=−6(x+9) ( y + 3 ) = − 6 ( x + 9 )

Step-by-step explanation:

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Identify the variable(s) in the expression below.<br> 5 + 12w
tatiyna

Answer:

w is the variable

Step-by-step explanation:

the letters you see next to the numbers the variable.

8 0
2 years ago
Select all the ordered pairs that satisfy the function y = 3x + 5. A. (2, –1) A. , (2, –1) B. ( –3, –4) B. , ( –3, –4) C. ( 4, 1
Ne4ueva [31]

Answer:

B. ( –3, –4)

C. ( 4, 17 )

Step-by-step explanation:

Function: y = 3x + 5

Using method of elimination

A. (2, –1)

x = 2, y = -1

-1 = 3 (2) + 5

-1 ≠ 11

This option is incorrect!

B. ( –3, –4)

x = -3, y = -4

-4 = 3 (-3) + 5

-4 = - 9 + 5

-4 = -4

This option is correct!

C. ( 4, 17 )

x = 4, y = 17

17 = 3 (4) + 5

17 = 12 + 5

17 = 17

This option is correct!

D. ( 3, 8 )

x = 3, y = 8

8 = 3 (3) + 5

8 = 9 + 5

8 = 14

This option is incorrect!

5 0
3 years ago
Henry knows that the circumference of a circle is 18mc006-1.jpg inches. What is the area of the circle?
lesantik [10]
The complete question is:
Henry knows that the circumference of a circle is 18π inches. What is the area of the circle?

Solution:
Circumference (C) of the circle can be written as:

C=2 \pi r \\ \\ 18 \pi =2 \pi r \\ \\ r=9

Using this value of radius, we can find the Area(A) of the circle.

A= \pi  r^{2}  \\  \\ &#10;A= \pi (9)^{2}  \\  \\ &#10;A=81 \pi

Therefore, area of the circle having a circumference of 18π inches will be 81π inches²
5 0
3 years ago
Using Synthetic Division Use synthetic division to find the expression for the area of the base of a rectangular prism with heig
SOVA2 [1]
The answer is x2<span> – 2</span>x<span> – 9 and that is option C</span>
4 0
3 years ago
Read 2 more answers
Use special right triangles to find the exact value (no decimals).
fgiga [73]

Let’s find some exact values using some well-known triangles. Then we’ll use these exact values to answer the above challenges.

sin 45<span>°: </span>You may recall that an isosceles right triangle with sides of 1 and with hypotenuse of square root of 2 will give you the sine of 45 degrees as half the square root of 2.

sin 30° and sin 60<span>°: </span>An equilateral triangle has all angles measuring  60 degrees and all three sides are equal.  For convenience, we choose each side to be length 2.  When you bisect an angle, you get 30 degrees and the side opposite is 1/2 of 2, which gives you 1.  Using that right triangle, you get exact answers for sine of 30°, and sin 60° which are 1/2 and the square root of 3 over 2 respectively.

Now using the formula for the sine of the sum of 2 angles,

sin(A + B) = sin A cos<span> B</span> + cos A sin B,

we can find the sine of (45° + 30°) to give sine of 75 degrees.

We now find the sine of 36°, by first finding the cos of 36°.

<span>The cosine of 36 degrees can be calculated by using a pentagon.</span>

<span>that is as much as i know about that.</span>

5 0
3 years ago
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