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sergey [27]
3 years ago
7

Classify the following polynomial by degree and the number of terms.

Mathematics
1 answer:
Vikki [24]3 years ago
6 0
Not too sure but I think it’s A. Linear Trinomial

Hope it helps!
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What is the horizontal distance between the two points (-7,-4) and (12,-4)? Remember that distance is always positive! Hint: The
RSB [31]
<h3>Answer: 19</h3>

==================================================

Explanation:

Draw out a number line. Plot -7 and 12 on the number line. Draw in the tickmarks between them. You should find the distance from -7 to 12 is 19 units since you need to go 19 spaces from either -7 to 12, or vice versa.

You can use subtraction to get

-7-12 = -19

or

12-(-7) = 12+7 = 19

The final result is made positive since negative distance does not make sense.

So you'd have |-7-12| = |-19| = 19 or |12-(-7)| = |19| = 19.

All of this only works because the two y coordinates are the same, which makes a horizontal line through the two given points.

7 0
3 years ago
Please Help Me Answer this question
slamgirl [31]
The answer is 3/5
Just keep the distributive property in mind.
7 0
3 years ago
1)Alexpleyadefn
Anarel [89]

Answer:

Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
Kara and Steven are biking around a 1,800 kilometer path. They start biking from the same place, at the same time, and in the sa
levacccp [35]
It would take them 120 hours to get to the same point on the path again.

Kara is traveling at half the speed of Steven. Therefore, we Steven finishes his second lap Kara will just be finishing her first lap. They will both be at the starting lap again.

It will take Kara 120 hours to complete the lap. 
1800 / 15 = 120  

(That is a lot of time, do you have the numbers correct?)
3 0
3 years ago
Match each graph with its corresponding equation
s344n2d4d5 [400]
The equation of the parabolas given will be found as follows:
a] general form of the parabolas is:
y=k(ax^2+bx+c)
taking to points form the first graph say (2,-2) (3,2), thus
y=k(x-2)(x-3)
y=k(x^2-5x+6)

taking another point (-1,5) 
5=k((-1)^2-5(-1)+6)
5=k(1+5+6)
5=12k
k=5/12
thus the equation will be:
y=5/12(x^2-5x+6)

b] Using the vertex form of the quadratic equations:
y=a(x-h)^2+k
where (h,k) is the vertex
from the graph, the vertex is hence: (-2,1)
thus the equation will be:
y=a(x+2)^2+1
taking the point say (0,3) and solving for a
3=a(0+2)^2+1
3=4a+1
a=1/2
hence the equation will be:
y=1/2(x+2)^2+1


5 0
3 years ago
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