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3 years ago

If 3 bananas cost of 50 cents, how many bananas can be bought for 20 dollars?

Mathematics

1 answer:

GuDViN [60]3 years ago

6 0

Answer:

120 bananas

Step-by-step explanation:

$20 = 2000 cents

Create a proportion:

Cross multiply, then divide: 3 × 2000 = 6000, 6000 ÷ 50 = 120

So, you can buy 120 bananas for $20

hope this helps

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Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the

Alexxandr [17]

Answer:

Step-by-step explanation:

The table can be computed as:

Advertising Expenses ($ million) Number of companies

25 up to 35 4

35 up to 45 19

45 up to 55 27

55 up to 65 16

65 up to 75 9

TOTAL 75

Let's find the probabilities first:

$P(25 - 35) = P \Big(\dfrac{25-50.93}{10.80}$

For 35 up to 45

$P(35 - 45) = P \Big(\dfrac{35-50.93}{10.80}$

For 45 up to 55

$P(45 - 55) = P \Big(\dfrac{45-50.93}{10.80}$

For 55 up to 65

$P(55 - 65) = P \Big(\dfrac{55-50.93}{10.80}$

For 65 up to 75

$P(65 - 75) = P \Big(\dfrac{65-50.93}{10.80}$

Chi-Square Table can be computed as follows:

Expense No of Probabilities(P) Expe $(O-E)^2$ $\dfrac{(O-E)^2}{E}$

compa cted E (n*p)

nies (O)

25-35 4 0.0612 75*0.0612 = 4.59 0.3481 0.0758

35-45 19 0.2218 75*0.2218 = 16.635 5.5932 0.3362

45-55 27 0.3568 75*0.3568 = 26.76 0.0576 0.021

55-65 16 0.2552 75*0.2552 = 19.14 9.8596 0.5151

65-75 9 0.0839 75*0.0839 = 6.2925 7.331 1.1650

$\sum \dfrac{(O-E)^2}{E}= 2.0492$

Using the Chi-square formula:

$X^2 = \dfrac{(O-E)^2}{E} \\ \\ Chi-square \ X^2 = 2.0942$

Null hypothesis:

$H_o: \text{The population of advertising expenses follows a normal distribution}$

Alternative hypothesis:

$H_a: \text{The population of advertising expenses does not follows a normal distribution}$

Assume that:

$\alpha = 0.02$

degree of freedom:

= n-1

= 5 -1

= 4

Critical value from $X^2 = 11.667$

Decision rule: To reject $H_o \ if \ X^2$ test statistics is greater than $X^2$ tabulated.

Conclusion: Since $X^2 = 2.0942$ is less than critical value 11.667. Then we fail to reject $H_o$

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3 years ago

3x-10>4+7x-3 Please explain.

larisa [96]

3x-10>4+7x-3

3x-10>1+7x

-4x-10>1

-4x>11

x<-11/4

Hope Your Thanksgiving Goes Well, Here's A Turkey

-TheKoolKid1O1

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The value of the 4th term is 80. the sequence is being doubled each step what is the 7th term?

leva [86]

This is a geometric sequence with common ratio (r) = 2.
an = ar^(n - 1)
a4 = a(2)^(4 - 1) = a(2)^3 = 8a
8a = 80
a = 80/8 = 10

7th term (a7) = 10(2)^(7 - 1) = 10(2^6) = 10(64) = 640

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3 years ago

Plz hury plz What type of graph is best to use to organize numerical data based on their digits to compare value?

katovenus [111]

Answer:

Step-by-step explanation:

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3 years ago

Match the reasons with the statements in the proof.

natta225 [31]

1. m∠6=m∠8, b||c
Given

2. m∠7=m∠8
If lines ||, corresponding angles =.

3. m∠6=m∠7
Substitution

4. a||b 
If alternate interior angles equal, then lines ||.

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3 years ago

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