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3 years ago

Please help me I don’t understand this question

Physics

1 answer:

GREYUIT [131]3 years ago

6 0

Answer: 225N to the right

Explanation:

The pedaling force is to the right and of 325N.

The air resistance is to the opposite side (in this case to the left) of 100N.

To find Net force of an object with two opposite forces acting on them then we have to subtract the smaller force from the bigger force and but the direction of the bigger force, so

325N-100N=225N

The greater force is towards the right proving the direction of the Net force is to the right.

Therefore the Net force is 225N to the right.

Please mark me brainliest.

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xz_007 [3.2K]

Answer:

ITS THE LAST ONE(4TH), I THINK

Explanation:

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3 years ago

Read 2 more answers

What force is needed to give a 4800.0 kg truck an acceleration of 6.2 m/s2 over a level road?

tekilochka [14]

Answer:

the force needed to give the truck the acceleration is 29,760 N.

Explanation:

Given;

mass of truck, m = 4800 kg

acceleration of the truck, a = 6.2 m/s²

The force needed to give the truck the acceleration is calculated as;

F = ma

F = 4800 x 6.2

F = 29,760 N

Therefore, the force needed to give the truck the acceleration is 29,760 N.

6 0

3 years ago

A mass weighting 48 lbs stretches a spring 6 inches. The mass is in a medium that exerts a viscous resistance of 27 lbs when the

Mademuasel [1]

Answer:

$u(t)=0.499ft.e^{-\frac{144.76lb/s}{2(48lb)}t}cos(\omega t)\\\\u(t)=0.499ft.e^{-1.5t}cos(\omega t)$

m = 48lb

b = 144.76lb

Explanation:

The general equation of a damping oscillate motion is given by:

$u(t)=u_oe^{-\frac{b}{2m}t}cos(\omega t-\alpha)$ (1)

uo: initial position

m: mass of the block

b: damping coefficient

w: angular frequency

α: initial phase

a. With the information given in the statement you replace the values of the parameters in (1). But first, you calculate the constant b by using the information about the viscous resistance force:

$|F_{vis}|=bv\\\\b=\frac{|F_{vis}|}{v}\\\\|F_{vis}|=27lbs=27*32.17ft.lb/s^2=868.59ft.lb/s^2\\\\b=\frac{868.59}{6}lb/s=144.76lb/s$

Then, you obtain by replacing in (1):

6in = 0.499 ft

$u(t)=0.499ft.e^{-\frac{144.76lb/s}{2(48lb)}t}cos(\omega t)\\\\u(t)=0.499ft.e^{-1.5t}cos(\omega t)$

mass, m = 48lb

b = 144.76 lb/s

8 0

3 years ago

An ambulance is currently traveling at 25 m/s, and is accelerating with a constant acceleration of 5 m/s^2. The ambulance is att

bazaltina [42]

Answer:

PLEASE MARK ME BRAINLIEST!!!

Explanation:

Given initial velocity of ambulance

v0=18m/s , acceleration a=5m/s2

To find distance, x=?

First we need to calculate the time for which it acquires 30\,m/s. For that use equation

v=v0+at

30=18+5×t

⇒t=30−185=125seconds

Distance travelled by the ambulance

x=v0t+12at2

x=(18×125)+12×5×(125)2

x=43.2+2.5×5.76=43.2+14.4

x=57.6m

Therefore the ambulance has to travel 57.6 m to match the velocity of car.

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2 years ago

A 1.65 mol sample of an ideal gas for which Cv,m = 3R/2 undergoes the following two-step process:1) from an initial state of the

kirill [66]

Answer:

W = -1.97KJ, Q = 1.97KJ, Delta U = 0

Delta U = -1.03KJ, Q = -1.03KJ, Delta H = -1.72KJ

Explanation:

The deatiled step by step calculation using the ideal gas equation (Pv =nRT), The first law of thermodynamics ( dQ =dW + dU) as applied is as shown in the attached file.

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4 years ago