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UkoKoshka [18]
4 years ago
14

For a science experiment you need to electroplate zinc onto both sides of a very thin, 1.00 cm x 1.00 cm copper sheet. You want

the zinc thickness to be 140 nm , and you know that the charge carriers in the ionic solution are divalent (charge 2e) zinc ions. The density of zinc is 7140 kg/m3 .If the electroplating apparatus operates at 1.40 A, how long (in seconds) will it take the zinc to reach the desired thickness?Please explain.
Physics
1 answer:
Serhud [2]4 years ago
4 0

Answer:

Explanation:

volume of zinc electroplated =2 x 1 x 10⁻² x 1 x 10⁻² x 140 x  10⁻⁹ = 280 x 10⁻¹³ .m³³

mass of zinc = 280 x 10⁻¹⁴ x 7140 kg = 19.992 x10⁻⁹ kg.

charged required to electroplate 65 g of Zn is 2 x 96500C

Charged required to electroplate 9.996 x 10⁻⁹ kg = 2 x (96500000 / 65) x 19.992 x 10⁻⁹   =( 2 x 965 x 19.992/65) x 10⁻⁴ .

=593.6 x 10⁻⁴ .C

Q = I X t

593.6 x 10⁻⁴ = 1.4 t

t =( 593.6 / 1.4 )x 10⁻⁴ = 42.4 x 10⁻³ s = 42.4 ms.  

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Answer:

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Explanation:

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Where:

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α : angular acceleration (rad/s²)

ω₀ : initial angular speed ( rad/s)

ωf : final angular speed   ( rad/s)

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ac = ( ω)²*(R)

ac = (8.68)²*(0.2)

ac = 15.07  m/s²

We replace data in the formula (2)

ac = v²/ R

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