Question

Interactive Solution 22.61 offers one approach to problems such as this one. The secondary coil of a step-up transformer provides the voltage that operates an electrostatic air filter. The turns ratio of the transformer is 45:1. The primary coil is plugged into a standard 120-V outlet. The current in the secondary coil is 2.0 x 10-3 A. Find the power consumed by the air filter.

Answer 1

Answer:

The power consumed by air filter is 10.8W

Explanation:

Voltage V=120 V

Current I=2.0×10⁻³A

Turn ration of transformer=45:1

To find

The power consumed by the air filter

Solution

The power used by filter is

$P=I_{p}V_{p}\\Solving \\\frac{I_{s}}{I_{p}}=\frac{N_{p}}{N_{s}}\\ shows\\I_{p}=I_{s}(\frac{N_{s}}{N_{p}})$

Substituting this result for power

$P=I_{p}V_{p}\\P=I_{s}(\frac{N_{s}}{N_{p}})V_{p}\\P=(2.0*10^{-3}A)(\frac{45}{1} )(120V)\\P=10.8W$

The power consumed by air filter is 10.8W