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kumpel [21]
3 years ago
10

Two children are pulling and pushing a 30.0 kg sled. The child pulling the sled is exerting a force of 12.0 N at a 45o angle. Th

e child pushing the sled is exerting a horizontal a force of 8.00 N. There is a force of friction of 5.00 N. What is the acceleration of the sled? Round the answer to the nearest hundredth

Physics
2 answers:
irinina [24]3 years ago
5 0
I'm not quite sure what happens to Fay so I didn't finish but hope it helps

bulgar [2K]3 years ago
5 0

Answer:

The weight is: 294 N

The normal force is 286 N

The acceleration is: -0.38 m/s²

Explanation:

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Answer:

Part A:

Displacement\ vector= -40\hat i+20\hat j+25\hat k

Part B:

Magnitude of displacement=44.721359 m

Explanation:

Given Data:

40 m in negative direction of the x axis

20 m perpendicular path to his left (considering +ve y direction)

25 m up a tower (Considering +ve z direction)

Required:

  • In unit-vector notation, what is the displacement of the sign from start to end.
  • The magnitude of the displacement of the sign from start to this new end=?

Solution:

Part A:

Displacement= (0-40)\hat i+(0+20)\hat j+(0+25)\hat k\\Displacement= -40\hat i+20\hat j+25\hat k

where:

i,j,k are unit vectors

Part B:

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Displacement= -40\hat i+20\hat j+0\hat k

Magnitude of displacement:

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