Answer:
emf will also be 10 times less as compared to when it has fallen 
Explanation:
We know, from faraday's law-

and 
So, as the height increases the velocity with which it will cross the ring will also increase. 
Given


Now, from 

From equation a and b we see that velocity when dropped from  is 10 times greater when height is 40
 is 10 times greater when height is 40  so, emf will also be 10 times less as compared to when it has fallen
 so, emf will also be 10 times less as compared to when it has fallen 
 
        
             
        
        
        
The initial kinetic energy of the car is

Then, the velocity of the car is decreased by half: 

so, the new kinetic energy is

So, the new kinetic energy is 1/4 of the initial kinetic energy of the car. Numerically:
 
 
        
        
        
Answer:
v = 5.15 m/s
Explanation:
At constant velocity, the cable tension will equal the car weight of 984(9.81) = 9,653 N
As the cable tension is less than this value, the car must be accelerating downward.
7730 = 984(9.81 - a)
a = 1.95 m/s²
kinematic equations s = ut + ½at² and v = u + at
-5.00 = u(4.00) + ½(-1.95)4.00²
u = 2.65 m/s    the car's initial velocity was upward at 2.65 m/s
v = 2.65 + (-1.95)(4.00)
v = -5.15 m/s
 
        
             
        
        
        
Answer:
D gravity
Explanation:
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