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BartSMP [9]
3 years ago
15

A certain electric dipole consists of charges q and –q separated by distance d, oriented along the x-axis as shown in the figure

. find an expression for the magnitude of the electric field e of the dipole at a point far away in the y-direction, a distance r away from the midpoint of the dipole. assume that r is much greater than
d. enter your answer in terms of q, d, r, and ε0.
Physics
1 answer:
Anna71 [15]3 years ago
7 0

Electric field due to a point charge is given by formula

E = \frac{kq}{r^2 + \frac{d^2}{4}}

now due to negative charge also the magnitude of electric field will be same

only difference is the direction of field due to negative charge is radially inwards

now we can say that net field due to these two charges is given as

E = 2E_0cos\theta

E = 2\frac{kq}{r^2 + \frac{d^2}{4}}*\frac{d/2}{\sqrt{r^2 + \frac{d^2}{4}}}

E = \frac{kqd}{(r^2 + \frac{d^2}{4})^1.5}

now it is given that distance r is very large than "d" so we can say

E = \frac{kqd}{r^3}

<em>so above is the electric field due to dipole</em>

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horsena [70]

Answer:

emf will also be 10 times less as compared to when it has fallen 40 \mathrm{m}

Explanation:

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e m f=-N \frac{\Delta \Phi}{\Delta T}

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Given

\mathrm{V} 1(\text { Speed at } 40 \mathrm{m})=2 \mathrm{x} \mathrm{V} 2(\text { speed at } 10 \mathrm{m})

\sqrt{2 g h_{2}}=2 \times \sqrt{2 g h_{1}}=28.28 \mathrm{m} / \mathrm{s}

Now, from 40 \mathrm{cm}

V_{3}=\sqrt{2 g h_{3}}=\sqrt{2 \times 10 \times 0.4}=2.82 \mathrm{m} / \mathrm{s}

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4 0
3 years ago
A car has a kinetic energy of 1.9 × 10^3 joules. If the velocity of the car is decreased by half, what is its kinetic energy?
VLD [36.1K]
The initial kinetic energy of the car is
E_1 =  \frac{1}{2}mv_1^2 =  1.9 \cdot 10^3 J

Then, the velocity of the car is decreased by half: v_2 =  \frac{v_1}{2}
so, the new kinetic energy is
E_2 =  \frac{1}{2}mv_2 ^2 =  \frac{1}{2} m ( \frac{v_1}{2} )^2= \frac{1}{2}m \frac{v_1^2}{4}= \frac{E_1}{4}
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When the mass of an object decreases, the force of gravity - Remains Unchanged - Decreases - increases - Becomes irregular
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The force of gravity decreases
5 0
3 years ago
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Signment
jeka94

Answer:

v = 5.15 m/s

Explanation:

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As the cable tension is less than this value, the car must be accelerating downward.

7730 = 984(9.81 - a)

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Answer:

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