Answer:
False.
Explanation:
When we create an array of size n, then it's index will starts from 0 to n-1. Array index starts with 0 because the first element of the array holds the memory location that refers to 0 element away.Similarly 2nd element of array is 1 distance away from that location. That is why index starts with 0 and goes to n-1 if the size is n.
In the question question, int list[25] is given. So the index will be from 0
to 25-1 only.If index will goes to 25 then it will go beyond the array.
Answer:
A closing tag
Explanation:
A tag in HTML is the core building block that marks the presence of an element. If the element has text or another element within it, it is marked using a two-sided tag and in which case, the opening tag indicates the content’s beginning and a closing tag indicates the end of the content
#include
Program: using namespace std;
string createPurchaseOrder0;
int main(
{
cout<return 0;
}
string createPurchaseOrder(
{
int qty;
double costPerltem;
string description,info="":
cout<<"Enter Quantity:
cin>>qty;
cout<<"Enter cost per item: "
cin>>costPerltem;
cout<<"Enter Description: "
cin>>description;
if(qty<0 I| costPerltem<0
Idescription.compare(''"')==0)
cout<<'InThe entered data is invalid!":
info="":
else
"
cout<<"'InThe entered data is valid!":
info=info+"'(nQuantity: "+to_string (qty) +" In";
info=info+"Cost per item:
"†to_string (costPerltem)+"In";
info=info+"Description: "description+" In";
return info;
Output:
So here is the code in Python:
n = 0.00 #this is a float because there are some numbers that are decimals.
while n < 20: #n which is 0.00 and while it is lower than 20 if runs the code below
n = n + 1 #it will add 1 to n everything it runs the code.
k = n / 2 #it will divide whatever n is everytime by 2
print(str(n) + '/2: ') # it's printing the number it's on
print(k) # prints the answer for the n.
You can change n to add by any, make n any num instead of 0.00 and you can change the while condition from n < 20 to any other logical statement. If you want to get creative you can take 2 inputs for numbers and make one of them the starting number and other one is the ending number. Also make sure to make n a number lower than you starting point because if you set n as your starting point then it will skip it.
Answer:
The answer to this question is given below in the explanation section.
Explanation:
The for-loop given in the question is:
for ( j = 0; j < 10; j++ )
{
appendItem (myList, aNumber); //this loop append a number to a list myList
}
This loop starts from J variable's value zero and when J's value is less than 10, the loop iterate through its body until J's value becomes greater or equal to 10. As J's value exceed nine, the loop will get terminated.
So this loop repeats 10 times its loop body, at the 11th time, the condition becomes false and the loop will get terminated.
