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BabaBlast [244]
3 years ago
8

What is an equation of the line perpendicular to y=1/5x+2 that contains (15,-4)

Mathematics
1 answer:
earnstyle [38]3 years ago
5 0

Answer:

y + 4 = -5(x - 15)

Step-by-step explanation:

The given line has a slope of 1/5.  Any new line perpendicular to this given line has a slope which is the negative reciprocal of 1/5:  -5.

Use the point-slope equation of a line:  y - k = m(x - h), where (h, k) is the point through which the new line passes.  Here h = 15 and k = -4, so we have:

y + 4 = -5(x - 15)

This line is perpendicular to the given line and also passes through (15, -4).

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Answer:

The Length of <em>JK</em> is 10

Step-by-step explanation:

Because <<em>J </em>is congruent to <<em>L</em> we know that the triangle in question must be isosceles as in an isosceles triangle two angles opposite of each other are equal. (This is also true for equilateral triangles, however, in an equilateral triangle all sides must be congruent, so we can rule equilateral out as <em>LJ </em>is not congruent to <em>KL.) </em>This means that the triangle must be isosceles.

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