What is an equation of the line perpendicular to y=1/5x+2 that contains (15,-4)

Mathematics

1 answer:

earnstyle [38]3 years ago

5 0

Answer:

y + 4 = -5(x - 15)

Step-by-step explanation:

The given line has a slope of 1/5. Any new line perpendicular to this given line has a slope which is the negative reciprocal of 1/5: -5.

Use the point-slope equation of a line: y - k = m(x - h), where (h, k) is the point through which the new line passes. Here h = 15 and k = -4, so we have:

y + 4 = -5(x - 15)

This line is perpendicular to the given line and also passes through (15, -4).

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