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BabaBlast [244]
2 years ago
8

What is an equation of the line perpendicular to y=1/5x+2 that contains (15,-4)

Mathematics
1 answer:
earnstyle [38]2 years ago
5 0

Answer:

y + 4 = -5(x - 15)

Step-by-step explanation:

The given line has a slope of 1/5.  Any new line perpendicular to this given line has a slope which is the negative reciprocal of 1/5:  -5.

Use the point-slope equation of a line:  y - k = m(x - h), where (h, k) is the point through which the new line passes.  Here h = 15 and k = -4, so we have:

y + 4 = -5(x - 15)

This line is perpendicular to the given line and also passes through (15, -4).

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jek_recluse [69]
We have to know the angle that is not labelled. (lets call it y) 
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and the sum of the angles of a triangle is 180 
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3 years ago
Explain how counting number of girls in five children family can be treated as a binomial experiment. What assumptions are neces
Juliette [100K]

This is a binomial experiment and you'll use the binomial probability distribution because:

  1. There are two choices for each birth. Either you get a girl or you get a boy. So there are two outcomes to each trial. This is where the "bi" comes from in "binomial" (bi means 2).
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Since all of those conditions above are met, this means we have a binomial experiment.

Some textbooks may split up item #2 into two parts, but I chose to place them together since they are similar ideas.

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3 years ago
X2 - 6x + 12 and y = 2x - 4, algebraically are
olga_2 [115]

<em><u>The solution is (4, 4)</u></em>

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

y = x^2 - 6x + 12 ------ eqn\ 1\\\\y = 2x - 4 ---------- eqn\ 2

<em><u>Substitute eqn 2 in eqn 1</u></em>

x^2 - 6x + 12 = 2x - 4

Make the right side of equation 0

x^2 - 6x + 12 - 2x + 4 = 0\\\\x^2 -8x + 16 = 0

<em><u>Solve by quadratic equation</u></em>

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=-8,\:c=16:\\\\x=\frac{-\left(-8\right)\pm \sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:16}}{2\cdot \:1}\\\\x=\frac{-\left(-8\right)\pm \sqrt{0}}{2\cdot \:1}\\\\x = \frac{8}{2}\\\\x = 4

<em><u>Substitute x = 4 in eqn 2</u></em>

y = 2(4) - 4

y = 8 - 4

y = 4

Thus solution is (4, 4)

5 0
3 years ago
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