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BabaBlast [244]
2 years ago
8

What is an equation of the line perpendicular to y=1/5x+2 that contains (15,-4)

Mathematics
1 answer:
earnstyle [38]2 years ago
5 0

Answer:

y + 4 = -5(x - 15)

Step-by-step explanation:

The given line has a slope of 1/5.  Any new line perpendicular to this given line has a slope which is the negative reciprocal of 1/5:  -5.

Use the point-slope equation of a line:  y - k = m(x - h), where (h, k) is the point through which the new line passes.  Here h = 15 and k = -4, so we have:

y + 4 = -5(x - 15)

This line is perpendicular to the given line and also passes through (15, -4).

You might be interested in
47 was divided by the power of ten to get 0.047 what power of ten was divided
Dmitrij [34]

Answer:

1,000

Step-by-step explanation:

47 to 0.047 moves 3 places

47, 4.7, 0.47, 0.047

this means that the power of then used should have 3 0's

making the power of ten 1,000

3 0
3 years ago
The ruby throated hummingbird has a wingbeat of about 200 beats per second about how many wing Beats would a hummingbird have in
Nady [450]
36,000 wing beats

60 sec= 1 minute 60*3=180sec/3minutes

180*200=36,000

4 0
3 years ago
I need help on this, please explain
san4es73 [151]

Answer:

The answer would be A

Step-by-step explanation:

When you draw TV with V being the midpoint of SU, you would have two triangles that are congruent on all three sides (SSS). See picture. Hope this helped :)

3 0
3 years ago
AYUDA CON ESTO!!! ALGUIEN PORFAVOR
Gre4nikov [31]

Answer:

Problem 1)  frequency:  160 heartbeats per minute, period= 0.00625 minutes (or 0.375 seconds)

Problem 2) Runner B has the smallest period

Problem 3) The sound propagates faster via a solid than via air, then the sound of the train will arrive faster via the rails.

Step-by-step explanation:

The frequency of the football player is 160 heartbeats per minute.

The period is (using the equation you showed above):

Period = \frac{1}{frequency} = \frac{1}{160} \,minutes= 0.00625\,\,minutes = 0.375\,\,seconds

second problem:

Runner A does 200 loops in 60 minutes so his frequency is:

\frac{200}{60} = \frac{10}{3} \approx  3.33   loops per minute

then the period is: 0.3 minutes (does one loop in 0.3 minutes)

the other runner does 200 loops in 65 minutes, so his frequency is:

\frac{200}{65} = \frac{40}{13} \approx  3.08   loops per minute

then the period is:

\frac{13}{40} =0.325\,\,\,minutes

Therefore runner B has the smaller period

8 0
3 years ago
Solve.
jekas [21]
<span>A. {+8) is the answer
</span>
6 0
3 years ago
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