Calculate the surface area of a hockey puck with a height of 1 in. and a diameter of 3 in
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Given, arc QR is congruent to arc LN and arc OP is congruent to arc VW.
And the expressions for each arc in the diagram also given as:
Arc QR = 2x - y, arc LN = 11 , arc OP= 10 and arc VW=5x+y.
Hence, we will get the system of equations as following:
Arc QR = Arc LN
2x - y = 11 ...(1)
Arc OP = Arc VW
5x + y = 10 ...(2)
We need to find the value of x. So, we can add the equations to eliminate y so that we can solve the equations for x. Therefore,
2x+5x = 11 + 10
7x = 21
Divide each sides by 7.
So, x= 3
The graph can be drawn by the placing the points and after translation points becomes A'(-3, -5), B'(-2, 3), C'(1, 4), and D'(0, -5)
<h3>What is quadrilateral?</h3>It is defined as the four-sided polygon in geometry having four edges and four corners.
We have:
Quadrilateral ABCD with vertices A(2,-3), B(3,5), C(6,6) and D(5,-3)
We can graph it on the coordinate plane as shown in the picture.
After applying the translation (x, y)→(x−5, y−2), the points becomes:
A'(-3, -5)
B'(-2, 3)
C'(1, 4)
D'(0, -5)
Similarly, we can graph it on the coordinate plane (refer attached picture)
Thus, the graph can be drawn by the placing the points and after translation points becomes A'(-3, -5), B'(-2, 3), C'(1, 4), and D'(0, -5)
Learn more about the quadrilateral here:
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