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kati45 [8]
3 years ago
11

Calculate the surface area of a hockey puck with a height of 1 in. and a diameter of 3 in

Mathematics
1 answer:
uysha [10]3 years ago
6 0

Answer:

23.56

Step-by-step explanation:

2(\pi r^{2}) + 2\pirh

2(\pi 1.5^{2})+ 2\pi(1.5)(1)

23.56

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The measure of angle QPR = ??? degrees
Ostrovityanka [42]
The measure of angle QPR is 30 degrees
3 0
3 years ago
I barely ask questions but I really need help with #3 and a little with 4. On number four I got 1 1/20 which doesn’t seem right.
uranmaximum [27]
Let r, g and b represent red, green and blue.

r+g+b = 74

r=g-1

b=r+g

Again, r+g+b = 74.  Let's substitutte r+g for b:  r+g+(r+g) = 74.

Next, let's eliminate r.  Use r=g-1.  Then      g-1  + g + g-1 + g = 74

Combining the g terms,  4g - 2 = 74     => 4g = 76   =>  g = 19

Recall that r=g-1
and 
b=r+g

Find r.  If r=g-1, and g=19, then r = 19-1=18

Find b:  b = r+g = 18+19=37

So there are 37 blue candies, 18 red candies and 19 green candies.

Check:  37+18+19=74 ???  Yes.
8 0
4 years ago
Which choices are real numbers. Check all that apply. A. (-1024)^1/4. B. (-131072)^1/16. C. (-256)^1/9. D. (-531441)^1/13
vredina [299]

Answer:

B

Step-by-step explanation:

That is my final answer so I maybe wrong so don't take my word for it

4 0
3 years ago
Read 2 more answers
Show three ways to estimate 3/5×9 1/2 identify each method you use
Slav-nsk [51]
                                  
\frac{3}{5} x 9 \frac{1}{2}

= \frac{27}{10} = 2,7
6 0
3 years ago
Read 2 more answers
If tn = 4n+1, find t1, t2, t3, and tn+1. Express tn+1−tn in its simplest form.
Doss [256]

Answer:

t_1=5

t_2=9

t_3=13

t_{n+1}-t_n=4

Step-by-step explanation:

We have that:

t_n=4n+1

When we substitute n=1, we get:

t_1=4*1+1=5

When we substitute n=2 we get:

t_2=4*2+1=9

When we substitute n=3, we get:

t_3=4*3+1=13

When we substitute n=n+1, we get:

t_{n+1}=4*(n+1)+1=4n+5

Now

t_{n+1}-t_n=4n+5-(4n+1)

We expand and simplify to obtain:

t_{n+1}-t_n=4n+5-4n-1

t_{n+1}-t_n=4

3 0
3 years ago
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