The tan(-x) is the same thing as -tan(x). The tangent function is also the same thing as sin(x)/cos(x), right? So let's rewrite that tan in terms of sin and cos:
![[cos(x)][tan(-x)]](https://tex.z-dn.net/?f=%5Bcos%28x%29%5D%5Btan%28-x%29%5D)
is the same as
![[cos(x)][ -\frac{sin(x)}{cos(x)}]](https://tex.z-dn.net/?f=%5Bcos%28x%29%5D%5B%20-%5Cfrac%7Bsin%28x%29%7D%7Bcos%28x%29%7D%5D%20)
We can now cancel out the cos(x), which leaves us only with -sin(x) remaining. So your answer is A.
Answer:
Infinitely Many Solutions.
Step-by-step explanation:
x+2y=0
6y=-3x
y=-3/6x
y=-1/2x
x+2(-1/2x)=0
x-2/2x=0
x-x=0
0=0
infinitely many solutions

<em>hope </em><em>it</em><em> helps</em>
Answer:
The option u chose is the correct one