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Sophie [7]
3 years ago
14

What is the​ long-run cost function if the production function is qequals=33Lplus+22​K? Let the cost of each unit of L be w and

the cost of each unit of K be r. The​ long-run cost function is A. ​C(q)equals=wplus+r. B. ​C(q)equals=​(w/33​)q if ​(w/33​)less than or equals≤​(r/22​), and ​(r/22​)q otherwise. C. ​C(q)equals=q. D. ​C(q)equals=wq if wless than or equals≤​r, and rq otherwise. E. ​C(q)equals=​(w/33​)q if ​(w/33​)greater than or equals≥​(r/22​), and ​(r/22​)q otherwise.
Mathematics
1 answer:
user100 [1]3 years ago
4 0

Answer:

C(q)equals=​(w/33​)q if ​(w/33​)greater than or equals≥​(r/22​), and ​(r/22​)q otherwise.

Step-by-step explanation:

The production function is q = 33L + 22​K

Cost function is then, C = wL+ rK

Minimising the functions, we get:

σ = wL+ rK+ λ(q -33L -22K)

dσ/dL = w - λ33 = 0 ----------(1)

dσ/dK = r - λ22 = 0 -----------(2)

dσ/dλ = q -33L -22K ---------(3)

From equation (1) and (2)

w/r ⇒ λ33 / λ22 ⇒ ³³/₂₂

Or, w = r(³³/₂₂)

Substitute for 'w' in C

C = r(³³/₂₂)L + rK

C = r [(³³/₂₂)L + K]

Or, (³³/₂₂)L + K = C / r

So, C/r = q    or    r = C/q

recall that w = r(³³/₂₂)

∴ w = (³³/₂₂)C/q

So, cost function C = wL+ rK

Substitute for 'w' and 'r' in the equation

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(24xy^3-16x^2y^2+32x^2y)/8xy
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(24xy^3-16x^2y^2+32x^2y)/8xy 

  <span><span>(<span><span>‌<span><span><span><span><span>24x</span><span>y^3</span></span>−<span><span>16<span>x^2</span></span><span>y^2</span></span></span>+<span><span>32<span>x^2</span></span>y</span></span>8</span></span>‌x</span>)</span><span>(y)</span></span><span>  =<span><span><span>−<span><span>2<span>x^3</span></span><span>y^3</span></span></span>+<span><span>3<span>x^2</span></span><span>y^4</span></span></span>+<span><span>4<span>x^3</span></span><span>y^<span>2</span></span></span></span></span>

4 0
3 years ago
Two equivalent expressions have the same _____ even though they may be written in different ways.
Svetach [21]

Answer:

Value

Step-by-step explanation:

Value because order can be different and they can still be the same!

For example, 3x+2 = 2+3x different order but still are equivalent!

x = -2/3, so their values are equivalent!

Hope this helps!

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3 0
3 years ago
Read 2 more answers
Precal question please help I don’t understand
frez [133]

A) True.  The domain of both is: x ≥ 0

B) True. 1/2 is on the outside so it is vertical.  1/2 is between 0 and 1 so it shrinks.

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D) False. 1/2 is not on the inside with "x" so it is not horizontal.

Answer: A, B

8 0
3 years ago
2. The sum of two integers is 74. The larger is 26 more than twice the smaller. Find the two integers.
kompoz [17]
74=x+y is the equation at the beginning we will say that x is the smaller number and y is the larger one. Now we substitute the larger number (y) for 26+2x. Plug that into the beginning equation to get 74= x+ 26+2x. Now solve.
74=3x+26
48=3x
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So we know that our smaller number is 16. To find the larger number we plug the value of the smaller number into the equation for the larger number like this.
y=26+2x
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So to check our answer we can plug in both values into the beginning equation.
74=58+16
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So to sum this up the smaller number is 16 and the larger number is 58.

4 0
3 years ago
Point A is located at (2, 6), and point M is located at (−1, 8). If point M is the midpoint of segment AB, find the location of
Viefleur [7K]

ANSWER:

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STEP-BY-STEP EXPLANATION:

The midpoint has the following definition:

\left(x_m,y_m\right)=\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right)

We can calculate point B, using the following equations obtained taking into account the above:

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The correct answer is: d. (−4, 10)

8 0
1 year ago
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