Using two points to find the slope use
y2-y1/x2-x1
i chose points (0,4) and (2,14)
14-4/2-0
10/2
5
The slope is 5
(jk)(x)= j (k(x)) = j(9-2x)
= -7(9-2x) = -63 + 14x
but i see there is no such option. may be second option is typo.
so you can select 2nd option
Answer:

Step-by-step explanation:

You add all fruit and times to 3/8 to find strawberries
Answer:
We have the equation:
(ax^2 + 3x + 2b) - (5x^2+bx-3c)= 3x^2 - 9
First, move all to the left side.
(ax^2 + 3x + 2b) - (5x^2+bx-3c) - 3x^2 + 9 = 0
Now let's group togheter terms with the same power of x.
(a - 5 - 3)*x^2 + (3 - b)*x + (2b + 3c + 9) = 0.
This must be zero for all the values of x, then the things inside each parenthesis must be zero.
1)
a - 5 - 3 = 0
a = 3 + 5 = 8.
2)
3 - b = 0
b = 3.
3)
2b + 3c + 9 = 0
2*3 + 3c + 9 = 0
3c = -6 - 9 = -15
c = -15/3 = -5
Then we have:
a = 8, b = 3, c = -5
a + b + c = 8 + 3 - 5 = 6