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ollegr [7]
3 years ago
6

What is the answer too 2y-3=-5

Mathematics
2 answers:
bogdanovich [222]3 years ago
8 0

2 − 3 = −5

First we need to Add 3 to both sides of the equation:

2 − 3 + 3 = −5 + 3

Then we simplify:

2 = −5 + 3

 2 = −2

Now we divide both sides of the equation by the same term:

2 / 2 = −2 / 2

Final answer: = −1

I hope this helps!

In-s [12.5K]3 years ago
4 0

Answer:

Y= - 1

Step-by-step explanation:

2y-3= - 5

  +3    +3

   2y= -2

   /2    /2

Y= -1

Step 1: Add 3 to both sides because you want to cancel out the 3 so you do the opposite of what is say's. For example, if it says 2y-3 add 3 or 2y+3 subtract 3 from both sides.

Step 2: Add 3 to -5 which would be -2

Step 3: Since you're "multiplying" Y to 2 you're going to divide 2 to get Y by itself. So 2/2 cancels out and now you're left with y

Step 4: Divide 2 form -2 and you get -1

Let me know if you have any questions and I hope this helps

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If (ax^2 + 3x + 2b) - (5x^2+bx-3c)=3x^2-9, what is the value of A + B + C?
Rina8888 [55]

Answer:

We have the equation:

(ax^2 + 3x + 2b) - (5x^2+bx-3c)=  3x^2 - 9

First, move all to the left side.

(ax^2 + 3x + 2b) - (5x^2+bx-3c) - 3x^2 + 9 = 0

Now let's group togheter terms with the same power of x.

(a - 5 - 3)*x^2 + (3 - b)*x + (2b + 3c + 9) = 0.

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