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vesna_86 [32]
3 years ago
5

Is the left kidney lower than the right kidney

Physics
2 answers:
qaws [65]3 years ago
7 0
Left kidney is higher
vazorg [7]3 years ago
3 0

left kidney is higher than the right kidney.

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a fire woman dropped a person onto the safety net. right before the person hit the net he had a velocity of 11.2m/s and 1800j of
Ludmilka [50]

Answer: 28.699

Explanation:

KE=1/2(mv²)

1800=1/2m (125.44)

14.349=2m

m=28.699

5 0
3 years ago
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If the results of a study do not support a hypothesis, it means that experiment failed
butalik [34]
No that is incorrect. If the results do not support the hypothesis than the hypothesis could have been incorrect. Or there is a possibility that the experiment was not done properly. A hypothesis is an educated guess for the results of the experiment. 
6 0
4 years ago
Explain why a man using a parachute falls through air slowly while a stone falls through air very fast
Korolek [52]

Answer:because the parachute is built so the wind will push up on it make the man/woman glide or fall slowly will a stone which has a lot of desentity

falls through the air faster do to is weight and shape .

Explanation:

3 0
3 years ago
Consider a person sliding down a water slide at constant velocity. what are the forces acting on the person as they slide? are t
Andru [333]

Explanation :

When a person is sliding with constant velocity, the forces that are acting on him are :

(1) Weight, W = mg where g is acceleration due to gravity.

(2) Friction forces acting opposite to the direction of motion.

(3) Normal force.

The forces acting on the person is balanced because the person is sliding with constant velocity.

From figure it is clear that, friction force is balanced by w\ sin\theta and normal is balanced by w\ cos\theta.

4 0
3 years ago
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A current of 16.0 mA is maintained in a single circular loop of 1.90 m circumference. A magnetic field of 0.790 T is directed pa
AVprozaik [17]

To solve this problem it is necessary to take into account the concepts related to the magnetic moment and the torque applied over magnetic moments.

For the case of the magnetic moment of a loop we have to,

\mu = IA

Where

I = Current

A = Area of the loop

Moreover the torque exerted by the magnetic field is defined as,

\tau = IAB

Where,

I = Current

A = Area of the loop

B = Magnetic Field

PART A) First we need to find the perimeter, then

P = 2\pi r

r = \frac{P}{2\pi}

r = \frac{1.9}{2\pi}

r = 0.3025m,

The total Area of the loop would be given as,

A = \pi r^2

A = \pi 0.3025^2

A = 0.287m^2

Substituting at the equation of magnetic moment we have

\mu = (16*10^{-3})(0.287)

\mu = 4.58*10^{-3} A.m^2

Therefore the magnetic moment of the loop is 4.58*10^{-3}Am^2

PART B)  Replacing our values at the equation of torque we have that

\tau = IAB

\tau = (16*10^{-3})(0.287)(0.790)

\tau = 3.62*10^{-3}Nm

Therefore the torque exerted by the magnetic field is 3.62*10^{-3}Nm

6 0
3 years ago
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