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Liono4ka [1.6K]
3 years ago
8

For an object spinning around a central point, what will happen if its distance from the center is decreased?

Physics
1 answer:
antoniya [11.8K]3 years ago
3 0

Answer:

Its acceleration will increase.

Explanation:

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Answer: A

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Which of these is an element?<br> O carbon<br> O<br> air<br> O carbon dioxide<br> water
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A truck is moving north word at a constant speed the momentum of the car is
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Part A Magnetic field lines form closed loops Magnetic field lines form closed loops Around and through bar magnets. Through cur
alex41 [277]

Answer:

Magnetic field lines form closed loops around current carrying straight wires.

Explanation:

Magnetic field lines is known to form closed loop (which also serves as a bar magnet) around current carrying conductor in a magnetic field. This direction of the loop around the conductor either clockwise or anticlockwise will determine the direction of current in the conductor.

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According to clenched fist rule which states if the conductor is grasp with the right hand, the curled finger will point in the direction of the magnetic field and the thumb will point in the direction of the current.

Note that the magnetic field lines around the conductor also behaves like a bar magnet.

8 0
3 years ago
If a diver-in-training is put into a pressurized suit, by how much would the pressure have to be raised (in atmospheres) above a
Sever21 [200]

This is an incomplete question, here is a complete question.

The bulk modulus for bone is 15.0 (GPa). If a diver-in-training is put into a pressurized suit, by how much would the pressure have to be raised (in atmospheres) above atmospheric pressure to compress her bones by 0.130% of their original volume?

Answer : The change in pressure will be, 1.95\times 10^7Pa

Explanation : Given,

Bulk modulus = 15.0GPa=15.0\times 10^9Pa

Change in volume = 0.130 % of original volume

Let the original volume be, V

So, Change in volume = \frac{0.130}{100}\times V

Formula used for change in pressure is:

\Delta P=\beta \frac{\Delta V}{V}

Now put all the given values in this formula, we get:

\Delta P=(15.0\times 10^9Pa)\times \frac{(\frac{0.130}{100}\times V)}{V}

\Delta P=1.95\times 10^7Pa

Thus, the change in pressure will be, 1.95\times 10^7Pa

8 0
3 years ago
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