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3 years ago

4. How much would an object accelerate if it has a mass of 25 kg and is pushed with a force of 2 Newtons?

Physics

1 answer:

slega [8]3 years ago

3 0

Answer:

0.4

Explanation:

f divided by m = a

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A student looks at ocean waves coming into the beach. An ocean wave with more energy will A) have a greater height. B) have a gr

attashe74 [19]

It would be A: Have a greater height.

The higher the wave the higher the energy!

3 0

3 years ago

Read 2 more answers

1. A sample of gas has a constant temperature and number of particles. As the volume of the gas sample is increased, the pressur

AURORKA [14]

Answer:

1.C

2.C

3.C

Explanation:

hope its help hehe:(

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3 years ago

The velocity of a free falling ball at different time intervals on unknown planet is shown in Figure 1.24.

dsp73

Answer:

a1 = (V2 - V1) / 1 s = 3.75 m/s^2

a2 = (V2 - V1) / (t2 - t1) = (7.5 - 3.75) / 1 s = 3.75 m/s^2

a3 = (V2 - V1) / (t2 - t1) = (7.5 - 3.75) / 1 s = 3.75 m/s^2

A) a = (a1 + a2 + a3) / 3 = 3.75 m/s^2

v = a (t2 - t1)

B) after 1 sec v = 3.75 m / sec^2 * 1 sec = 3.75 m/s

after 2 sec v = v0 + a t = 3.75 m/s + 3.75 m/s^2 * 1 s = 7.5 m/s

C) The velocity increases proportionaly to the time

D) One factor depends on the variation of the acceleration due to gravity because of different positions of measurement (on earth)

A much larger factor is due to air resisance of the air on the falling object

4 0

2 years ago

What are the effect of sound energy in air

ser-zykov [4K]

This will take me a little bit let me research :)

5 0

4 years ago

Lauryn serves a volleyball with a mass of 2.1 kg. The ball leaves her hand with a speed of 30 m/s.

Naya [18.7K]

Hi! Let's see.

<h3><u>TOPIC: Kinetic Energy.</u></h3>

Explanation:

Data:

Mass(m) = 2.1 kilograms
Speed(v) = 30 m/s
Kinetic Energy(Ek) = ?

==================================================================

Use the kinetic energy formula:

$\boxed{\boxed{\bold{E_{k}=\frac{m*(v)^{2}}{2}}}}$

Replace by the data:

$\boxed{E_{k}=\frac{2.1kg*(30\frac{m}{s})^{2}}{2}}}}}$

We multiply speed squared:

$\boxed{E_{k}=\frac{2.1kg*900\frac{m}{s}}{2}}}$

Multiply in the numerator, without forgetting the units:

$\boxed{E_{k}=\frac{1890J}{2}}}}$

Both numerator and denominador operations are divided:

$\boxed{\bold{E_{k}=945\ J}}$

Answer: The kinetic energy is <u>945 Joules.</u>

Cordially Alejanndraax. Greetings!

8 0

3 years ago