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Ugo [173]
3 years ago
8

SOMEONE PLEASEEEEEEEEEEEEEEEEEEEE HELPPPPPPPPPPPPPPP

Physics
1 answer:
Evgen [1.6K]3 years ago
8 0

Answer:

53.33 seconds

Explanation:

From the question;

  • Power of the motor is 75 kW or 75000 W
  • Depth or height is 150 m
  • Volume of water is 400 m³

We are required to determine taken to raise the water from the given height.

We know that density of water is 1000 kg/m³

Therefore;

Mass of water = 400 m³ × 1000 kg/m³

                       = 4.0 × 10^5 kg

Thus, force required to raise the water;

 = 4.0 × 10^5 kg × 10 N/kg

  = 4.0 × 10^6 N

To determine the time;

we use the formula;

 Time = work done ÷ power  

          = (4.0 × 10^6 N × 150 m) ÷ 75000 Joules/s

          = 53.33 seconds

Therefore, time taken to raise the water is 53.33 seconds

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In order to find the force (F), you would have to use the formula for it:
F=ma
where m is mass and a is acceleration.
In the problem, the mass is 2.85kg and the acceleration is 4.9m/s^2.
Therefore,
F=2.85kg(4.9m/s^2)
F=13.965kg(m/s^2)
Since N=kg(m/s^2)
F=13.965N
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F=13N
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Answer:

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in a lab, resonance tubes are used to determine experimentally the speed of sound. using the data given, evaluate the best appro
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<h3>What's the approximate speed of sound?</h3>

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3 0
2 years ago
When the valve between the 2.00-L bulb, in which the gas pressure is 2.00 atm, and the 3.00-L bulb, in which the gas pressure is
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Answer:

P_{C} = 3.2\, atm

Explanation:

Let assume that gases inside bulbs behave as an ideal gas and have the same temperature. Then, conditions of gases before and after valve opened are now modelled:

Bulb A (2 L, 2 atm) - Before opening:

P_{A} \cdot V_{A} = n_{A} \cdot R_{u} \cdot T

Bulb B (3 L, 4 atm) - Before opening:

P_{B} \cdot V_{B} = n_{B} \cdot R_{u} \cdot T

Bulbs A & B (5 L) - After opening:

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After some algebraic manipulation, a formula for final pressure is derived:

P_{C} = \frac{P_{A}\cdot V_{A} + P_{B}\cdot V_{B}}{V_{A}+V_{B}}

And final pressure is obtained:

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P_{C} = 3.2\, atm

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3 years ago
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