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OLEGan [10]
2 years ago
8

How many of sodium (Na) are needed to make 4.5 liters of a 1.5mol/L of Na solution?​

Chemistry
1 answer:
Salsk061 [2.6K]2 years ago
5 0

Answer:

Explanation:

First you will find the mole from the molarity and then the desired mass from the mole.

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there are 2 protons that are 5 cm apart. each proton has the same Elementary charge. what is the charge of each Proton​
tresset_1 [31]

Answer:

what are you looking for so that people can help you with it

8 0
3 years ago
A 0.4647-g sample of a compound known to contain only carbon, hydrogen, and oxygen was burned in oxygen to yield 0.01962 mol of
Scilla [17]

Answer:

The essence including its given problem is outlined in the following segment on the context..

Explanation:

The given values are:

Moles of CO₂,

x = 0.01962

Moles of water,

\frac{y}{2} =0.01961

y=2\times 0.01961

  =0.03922

Compound's mass,

= 0.4647 g

Let the compound's formula will be:

C_{x}H_{y}O_{z}

Combustion's general equation will be:

⇒  C_{x}H_{y}O_{z}+x+(\frac{y}{4}-\frac{z}{2}) O_{2}=xCO_{2}+\frac{y}{2H_{2}O}

On putting the estimated values, we get

⇒  12\times x=1\times y+16\times z=0.4647

⇒  12\times 0.01962+1\times 0.03922+16\times z=0.4647

⇒  0.27466+16z=0.4647

⇒                     z=0.01187

Now,

x : y : z = 0.01962:0.03922:0.01187

           = \frac{0.01962}{0.0118}:\frac{0.03922}{0.0188}:\frac{0.0188}{0.0188}

           = 1.6:3.3:1.0

           = 3:6:2

So that the empirical formula seems to be "C₃H₆O₂".

8 0
2 years ago
HELP FAST PLZ!!!
horsena [70]

Answer:

b

Explanation:

the baloon is made to hold more air.

7 0
3 years ago
WHAT IS THE STOCK NAME FOR FeSO^3
podryga [215]
Feso3 compound name

Iron(II) Sulfite FeSO3 Molecular Weight

Hope this helps!

Have a great day :)
4 0
3 years ago
3.75 g of an unknown gas at 59 °C and 1.00 atm is stored in a 1.35-L flask. What is the molar mass of the gas?
MAXImum [283]
You need to find moles of the gas, so you would use the ideal gas law:
PV=nRT
Pressure
Volume
n=moles
R= gas constant
Tenperature in Kelvin
n= PV/RT
(1.00atm)(1.35L)/(.08206)(332K) = 0.050mol
Molar mass is grams per mole, so
(3.75g/.050mol) = 75g/mol
4 0
3 years ago
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