Answer:
D. 4
Explanation:
Answer and Explanation: Carbon can form a maximum of four covalent bonds. Carbon can share up to four pairs of electrons, therefore, the carbon atom fills its outer energy level and achieves chemical stability.
Answer:
ptic fiber communication and satellite communication are the leading technologies which are revolutionizing the world of telecommunications. Both technologies have their advantages and limitations which make them suitable for certain type of applications. This article will provide an overview of optic fiber and satellite communication technologies and present a comparison of the features and related issues.
Optic Fiber Communication
Optic Fiber communication transmits information by sending pulses of light (using laser) through an optic fiber. The low signal loss in optic fibers and high data rate of transmission systems, allow signals with high data rates (exceeding several Gbps) to travel over long distances (more than 100 km) without a need of repeater or amplifier. Moreover, using wavelength division multiplexing (WDM) allows a single fiber to carry multiple signals (upto 10 different signals) of multi-Gbps transmissions. Optic Fiber communication offers extremely high bandwidth, immunity to electromagnetic interference, non-existent delays and immunity from interception by external means. In the 1980s and 1990s, the continents were linked together using undersea optic fiber bringing about a paradigm shift in the global telecommunications.
These advancements in optic fiber communication has resulted in decrease of satellite communications for several types of communications. For instance, transmission between fixed locations or point-to-point communications, where large bandwidths are required (such as transoceanic telephone systems) are made through optic fiber instead of using satellite communication. Optic Fiber communication is also used to transmit telephone signals, Internet communication, LAN (Gigabit LAN) and cable television signals.
Satellite Communication
Satellite communications use artificial satellites as relays between a transmitter and a receiver at different locations on Earth. Satellite systems allow users to bypass typical carrier offices and to broadcast information to multiple locations. Communications satellites are used for radio, TV, telephone, Internet, military and other applications. There are more than 2,000 satellites around Earth’s orbit, being used for communication by both government and private organizations.
Communication Satellites are LOS (line-of-sight) microwave systems with a repeater. These satellites rotate around the earth with the speed of earth and are known as geostationary satellites. The limitations of antenna size also limits focusing capability making the coverage for a single satellite transmitter very large. This makes satellite communication ideal for TV and radio services as the signal has to flow from a single point to many points in a single direction. The large distance of satellites from the earth (about 22,300 miles) results in delays which adversely effects two-way communication like mobile conversations. Low earth orbit satellites can be used for two-way mobile communication because less power is required to reach those satellites.
Explanation:
Answer :
(A) The dissociation reaction of
will be:

The equilibrium expression :
![K_a=\frac{[H^+][C_2H_3O_2^-]}{[HC_2H_3O_2]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BH%5E%2B%5D%5BC_2H_3O_2%5E-%5D%7D%7B%5BHC_2H_3O_2%5D%7D)
(B) The dissociation reaction of
will be:

The equilibrium expression :
![K_a=\frac{[H^+][Co(H_2O)_5(OH)^{2+}]}{[Co(H_2O)_6^{3+}]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BH%5E%2B%5D%5BCo%28H_2O%29_5%28OH%29%5E%7B2%2B%7D%5D%7D%7B%5BCo%28H_2O%29_6%5E%7B3%2B%7D%5D%7D)
(C) The dissociation reaction of
will be:

The equilibrium expression :
![K_a=\frac{[H^+][CH_3NH_2]}{[CH_3NH_3^+]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BH%5E%2B%5D%5BCH_3NH_2%5D%7D%7B%5BCH_3NH_3%5E%2B%5D%7D)
Explanation :
Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.
The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.
As we know that the concentrations of pure solids and liquids are constant that is they do not change. Thus, they are not included in the equilibrium expression.
(A) The dissociation reaction of
will be:

The equilibrium expression of
will be:
![K_a=\frac{[H^+][C_2H_3O_2^-]}{[HC_2H_3O_2]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BH%5E%2B%5D%5BC_2H_3O_2%5E-%5D%7D%7B%5BHC_2H_3O_2%5D%7D)
(B) The dissociation reaction of
will be:

The equilibrium expression of
will be:
![K_a=\frac{[H^+][Co(H_2O)_5(OH)^{2+}]}{[Co(H_2O)_6^{3+}]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BH%5E%2B%5D%5BCo%28H_2O%29_5%28OH%29%5E%7B2%2B%7D%5D%7D%7B%5BCo%28H_2O%29_6%5E%7B3%2B%7D%5D%7D)
(C) The dissociation reaction of
will be:

The equilibrium expression of
will be:
![K_a=\frac{[H^+][CH_3NH_2]}{[CH_3NH_3^+]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BH%5E%2B%5D%5BCH_3NH_2%5D%7D%7B%5BCH_3NH_3%5E%2B%5D%7D)
Answer:
D. the mass of one mole of a substance
Explanation:
The molar mass of a substance is the mass in grams of one mole of the substance.
- For an element, the molar mass is the relative atoms mass expressed in grams.
- For example 23g of Na, 40g of oxygen
- For compounds, molar mass is the gram -formula or gram - molecular weight.
- This is determined by the addition of its component atomic masses and then expressed in grams.
Answer:
Ratio is 3:2
3CO = 2Fe or 1.5 CO = 1 Fe
Explanation:
Fe2O3 + 3CO = 2Fe + 3CO2
Fe2O3 = Iron (|||) oxide
CO = Carbon monoxide
Fe = Solid Iron
CO2 = Carbon dioxide
Excellent is already balanced.
10 Moles Fe and 15 Moles of CO2
5 Moles Fe2O3 + 15 Moles 3CO = 10 Moles Fe + 15 Moles 3CO2
What is the ratio of carbon monoxide to solid iron
Ratio is 3:2 or 1.5 CO = 1 Fe