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Nady [450]
3 years ago
13

2y=12x-10 and y+=6x+12 Do the lines intersect, coincide, or are they parallel? 50 pts and ill give brainly to correct answer

Mathematics
2 answers:
astraxan [27]3 years ago
7 0

Answer:intersect

Step-by-step explanation:

NikAS [45]3 years ago
6 0

Answer:

parallel

Step-by-step explanation:

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Steven wishes to save for his retirement by depositing $2,000 at the beginning of each year for thirty years. Exactly one year a
Ad libitum [116K]

Step-by-step explanation:

i = interest 3% for 30 years

This is a simple dynamical system for whom the the solutions are given as

S=R[\frac{(i+1)^n-1}{i}](i+1)

putting values we get

S=2000[\frac{(1.03)^{30}-1}{0.03}](1.03)

= $98005.35

withdrawal of money takes place from one year after last payment

To determine the result we use the present value formula of an annuity date

P = R\frac{1-(1+i)^{-n}}{i}{i+1}

we need to calculate R so putting the values and solving for R we get

R= $6542.2356

8 0
3 years ago
(a) A newspaper conducted a statewide survey concerning the 1998 race for state senator. The newspaper took a SRS of 1200 regist
Sladkaya [172]

Answer:

n=9604

Step-by-step explanation:

1) Notation and definitions

X=620 number of people that would vote for the Republican candidate

n=1200 random sample taken

\hat p=\frac{620}{1200}=0.517 estimated proportion of people that would vote for the Republican candidate

p true population proportion of people that would vote for the Republican candidate

Me= 0.01 represent th margin of error.

Confidence =0.95 or 95%

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1- p)}{n}})

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.01 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

The problem says that we need to use \hat p =0.05, and replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.01}{1.96})^2}=9604  

And rounded we have that n=9604

6 0
3 years ago
Simplify the problem
Natasha2012 [34]
\frac{6}{10x^2} \div  \frac{6}{10x^3-60x^2}  = \frac{6}{10x^2} \cdot  \frac{10x^3-60x^2}{6}  =\frac{1}{10x^2} \cdot  \frac{10x^2(x-6)}{1}  =x-6
5 0
3 years ago
The lengths of pregnancies are normally distributed with a mean of 268 days and a standard deviation of 15 days. a. Find the pro
Bogdan [553]

Answer:

Step-by-step explanation:

Let X be the length of pregnancy.

X is N(268, 15)

a) Prob of pregnancy lasting 307 days or longer

= P(X>307) = P(Z>\frac{307-268}{15} )\\=P(Z>2.6)\\

=0.5-0.4953

=0.0047

b) Lowest 2% is 2nd percentile

Z=-2.55

X score = 268-2.55(15)

= 229.75 days

If length of days >230 days then it is not premature.

4 0
3 years ago
Maria jogged 3 miles in 3/5 hour. Kari jogged 2 1/2 miles in 1/2 hour. Tell whether each statement is True or False.
Margaret [11]

Answer:

I believe this is correct

A is FALSE

B is TRUE

C is FALSE

3 0
3 years ago
Read 2 more answers
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