<img src="https://tex.z-dn.net/?f=%5Cboxed%7B%5Csf%20%5Csqrt%7B200%7D%5Ctimes%20%5Csqrt%7B200%7D%20%7D" id="TexFormula1" title="

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3 years ago

\boxed{\sf \sqrt{200}\times \sqrt{200} }" alt="\boxed{\sf \sqrt{200}\times \sqrt{200} }" align="absmiddle" class="latex-formula">

Mathematics

2 answers:

Sergeu [11.5K]3 years ago

6 0

Answer:

$➝200$

Step-by-step explanation:

$➝ \sqrt{200 } \times \sqrt{200}$

$➝ \sqrt{200}$

$➝200$

Darya [45]3 years ago

3 0

Answer:

$\sf \longmapsto200$

Step-by-step explanation:

$\sf \longmapsto\sqrt{200}\times \sqrt{200}$

$\sf \longmapsto \sqrt{200}$

$\sf \longmapsto200$

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Solve the following system of equations . Plot the solution to the system on the provided graph

navik [9.2K]

Answer:

(6, -3)

Step-by-step explanation:

I will solve this system using elimination.

$[tex]\left \{ {{-x+2y=-12} \atop {2x+3y=3}} \right.$ [/tex]

I will multiply $-x+2y=-12$ by 2 so that -x becomes -2x.

2(-x + 2y = -12)

Distribute.

-2x + 4y = -24

Now subtract this from the other equation.

2x + 3y = 3

-2x + 4y = -24

7y = -21

Divide both sides by 7.

y = -3

Now that we have the value of y, plug it into the original equation.

-x + 2(-3) = -12

Simplify.

-x - 6 = -12

Add 6 to both sides.

-x = -6

Divide both sides by -1.

x = 6

(6, -3)

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3 years ago

For the x-values 1,2,3, and so on, the y-values of a function form a geometric sequence that increases in value. What type of fu

babymother [125]

Answer:

C) Exponential Growth

Step-by-step explanation:

The geometric sequence is of the form a(n) = a*r^(n-1). For example, a(n) = 2*3^(n-1) with a = 2 as the starting term and r = 3 as the common ratio.

The variable n is in the exponent. We can replace it with x to get y = 2*3^(x-1); which graphs out to an exponential curve going uphill as you read it from left to right. This shows exponential growth, which matches with the growth of the original geometric sequence.

7 0

3 years ago

Read 2 more answers

Geometry!!!!!!!!!!!!!!!!!!!!

svlad2 [7]

Answer:

The two triangles are related by Side-Side-Side (SSS), so the triangles can be proven congruent.

Step-by-step explanation:

There are no angles that can be shown to be congruent to one another, so this eliminates all answer choices with angles (SSA, SAS, ASA, AAA, AAS).

This leaves you with either the HL (Hypotenuse-Leg) Theorem or SSS (Side-Side-Side) Theorem. We could claim that the triangles can be proven congruent by HL, however, we aren't exactly sure as to whether or not the triangles have a right angle. There is no indicator, and in this case, we cannot assume so.

This leaves you with the SSS Theorem.

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3 years ago

Solve -0.25a + 3.8 = 4.6

julia-pushkina [17]

A would have to equal -3.2

7 0

3 years ago

injured runners train on a special track at a rehabilitation center. The track is a square with a half circle on its left and ri

diamong [38]

Answer:

The length of the track is approximately 51.7 ft

The track has three sides of the square and the distance round a half of a complete circle

Step-by-step explanation:

The given track shape and measurements are;

The shape on the left side of the track = Square

The shape on the right side of the track = Half circle

The area of the square on the the left side of the track = 128 square feet

Therefore, from the area, A, of a square of side length, s, which is s × s, and letting the side length of the square = s, we have;

Area of the square portion of the track = s × s = s² = 128 ft²

Therefore, s = √(128 ft²) = 8·√(2) ft.

Whereby the side length of the square is bounded by the diameter of the half circle, we have;

Length of the diameter of the half circle = s = 8·√(2) ft.

The length of the perimeter of the half circle = π·D/2 = π × 8·√(2)/2 = π × 4·√(2) ≈ 17.77 ft.

The perimeter of the track, which is the length of the track is made up of the three sides of the square opposite to the half circle and the circumference of the half circle.

Therefore;

The length of the track = 3 × 8·√(2) ft + π × 4·√(2) ft. = 4·√2×(π+6) ≈ 51.7 ft

The length of the track ≈ 51.7 ft

Which gives;

The track has three sides of the square and the distance round a half of a complete circle.

5 0

3 years ago