PLS HELP ASAP ILL GIVE BRAINLKEST THANKS

The women's recommended weight formula from harvard pilgrim healthcare says, "give yourself 100 lb for the first 5 ft plus 5 lb

romanna [79]

This would have to apply for a certain height compared to a weight or vice versa. I'm 5'8'' and for me that would mean I would have a healthy weight of 140 lbs.

3 0

2 years ago

Milena is trying to determine an algebraic expression to represent the amount of punch she needs to make for her party. She does

Rashid [163]

Answer:

let g = number of guests. if each guest is to have 3 cups we represent this as

3g

for the additional 20 cups, we add 20

3g + 20

6 0

2 years ago

What is seventy divided by four?

Nataly_w [17]

Answer:

17.5

Step-by-step explanation:

17×4=68; half of 4 is 2; 68+2=70

5 0

2 years ago

Read 2 more answers

How much time has passed from the first clock to the second clock?

bonufazy [111]

Answer:

Step-by-step explanation:

Time for first clock is 8:34

Time for second clock is 11:48

subtract them: 11 hrs. 48 min.

- 8 hrs. 34 min.

_____________

3 hrs. 14 min.

4 0

2 years ago

Company A makes a large shipment to Company B. Company B can reject the shipment if they can conclude that the proportion of def

boyakko [2]

Answer:

$z=\frac{0.1475-0.1}{\sqrt{\frac{0.1(1-0.1)}{400}}}=3.17$

The p value for this case would be given by:

$p_v =P(z>3.17)=0.00076$

For this case the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 0.1 and then Company B can reject the shipment

Step-by-step explanation:

Information provided

n=400 represent the random sample taken

X=59 represent number of defectives from the company B

$\hat p=\frac{59}{400}=0.1475$ estimated proportion of defectives from the company B

$p_o=0.1$ is the value to verify

$\alpha=0.05$ represent the significance level

z would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to verify if the true proportion of defectives is higher than 0.1 then the system of hypothesis are.:

Null hypothesis: $p \leq 0.1$

Alternative hypothesis: $p > 0.1$

The statistic would be given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the info given we got:

$z=\frac{0.1475-0.1}{\sqrt{\frac{0.1(1-0.1)}{400}}}=3.17$

The p value for this case would be given by:

$p_v =P(z>3.17)=0.00076$

For this case the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 0.1 and then Company B can reject the shipment

8 0

3 years ago