Answer:
a) 0.82
b) 0.18
Step-by-step explanation:
We are given that
P(F)=0.69
P(R)=0.42
P(F and R)=0.29.
a)
P(course has a final exam or a research paper)=P(F or R)=?
P(F or R)=P(F)+P(R)- P(F and R)
P(F or R)=0.69+0.42-0.29
P(F or R)=1.11-0.29
P(F or R)=0.82.
Thus, the the probability that a course has a final exam or a research paper is 0.82.
b)
P( NEITHER of two requirements)=P(F' and R')=?
According to De Morgan's law
P(A' and B')=[P(A or B)]'
P(A' and B')=1-P(A or B)
P(A' and B')=1-0.82
P(A' and B')=0.18
Thus, the probability that a course has NEITHER of these two requirements is 0.18.
<span>DE=EF hope I helped with your studies :)
</span>
The slope is (4,3). You look at the y intercept (where the y axis is crossed by the line) and simply count rise over run until you reach the next point. The next point from the y intercept (-2,0) is (2,3).
-2+4=2
0+3=3
And there you go. In fraction form it’s 4/3.
Hope this helped!
Answer:
the answer is y - 8
Step-by-step explanation:
just makes sense
