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timurjin [86]
2 years ago
13

Please take a look at the picture

Mathematics
1 answer:
Pavlova-9 [17]2 years ago
5 0

Answer: C

Step-by-step explanation:

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Find a solution to the ineqality x &gt; 6.<br> A. 4 <br> B. 11<br> C. 2<br> D. 6
Delicious77 [7]
It would be B. 11 is bigger then 6
5 0
3 years ago
Read 2 more answers
Find the percent of change from
Mashcka [7]

Answer:

option 4

Step-by-step explanation:

Percent change is calculated as

\frac{change}{original} × 100%

change = 15 - 10 = 5 , then

percent change = \frac{5}{10} × 100% = 5 × 10% = 50%

8 0
2 years ago
How is the graph of y = 8x2 − 1 different from the graph of y = 8x2?
BlackZzzverrR [31]

Answer:

since it's the lhs we are concerned about, i. e., Y axis, so it must be either up or down. now look at the question, it says 8x2 - (1), it means one lower value of y i. e., 1 unit down

5 0
3 years ago
Please help me with this!!!
Natalija [7]

Answer:

  {A, H, M, O, P, R, S, T} = {1, 7, 5, 0, 8, 6, 4, 9}

or

  {O, A, S, M, R, H, P, T} = {0, 1, 4, 5, 6, 7, 8, 9}

Step-by-step explanation:

Starting in the thousands column, we see the sum P+M+A mod 10 = M, so P + A = 10 or 11. That is, there is a carry to the next column of 1, meaning T + 1 = O, and that sum must also create a carry of 1, so S + 1 = M.

In order for T + 1 to generate a carry, we must have T = 9 and O = 0.

Now, consider the 10s column. This has 36 +A +(carry in) mod 10 = 9. So, A+(carry in) = 3.

Considering the 1s column, we have 9+0+2H+S = H+10 or H+20. We know H+S+9 cannot be 10, so it must be 20. That means H+S = 11, and (carry in) to the 10s column must be 2. Since A = 3 - (carry in), we must have A=1.

At this point, we have ... A=1, T=9, O=0, S+H=11, S+1=M.

Now, consider the 100s column. We know the carry in from the 10s column is 3, so we have 3+2A+R=A+10. Since we know A=1, this means 5+R=11, or R=6.

The carry in to the 1000s column is 1, so we have P+A+1 = 10, or P=8.

__

Our assignments so far are ...

  0 = O, 1 = A, 6 = R, 8 = P, 9 = T.

and we need to find S, M, and H such that M=S+1 and S+H=11. We know S and H cannot be 2, 3, or 5, because the 11's complement of those digits is already assigned. That leaves 4 and 7 for S and H, but we also need an unassigned value that is 1 more than S. These considerations make it necessary that S=4, M=5, H=7.

Then the addition problem is ...

  8197 + 90 + 5197 +491694 +19 = 505197

_____

Final assignments are ...

  O = 0, A = 1, S = 4, M = 5, R = 6, H = 7, P = 8, T = 9

4 0
3 years ago
What is the value of z which makes the expression x2 - 16x + x equivalent to ( x- 8 ) 2
diamong [38]

Answer:

x=64

Step-by-step explanation:

* change equivalent to to = *

now we have x² - 16x + x = (x-8)²

step 1 simplify both sides

(x)²=x²

-8x*2=16x

8=64

-16x + x = 15x

now we have x² -15x = x² - 16x + 64

step 2 subtract x² from each side

x² -x² = 0

x² - x² cancels out

now we have -15x = -16x + 64

step 3 add 16x to each side

-15x + 16x = x

-16x + 16x cancels out

we're left with x = 64

7 0
3 years ago
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