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Sladkaya [172]
4 years ago
5

When two gases or two liquids form a solution, the substance that is present in the largest amount is the?

Chemistry
1 answer:
skad [1K]4 years ago
4 0
Is the solvent (Hope this helped)
You might be interested in
The oxides of nitrogen are very important ingredients in determining urban air pollution. Name each of the following compounds.(
deff fn [24]

Answer:

(a) N₂O - Dinitrogen monoxide or Dinitrogen (I) oxide

(b) NO - Nitrogen monoxide or Nitrogen (II) oxide

(c) NO₂ - Nitrogen dioxide or Nitrogen (IV) oxide

(d) N₂O₅ - Dinitrogen pentoxide

(e) N₂O₄ - Dinitrogen tetraoxide.

Explanation:

To name each of the compounds,

(a) N2O; It is properly written as N₂O. N₂O is a colorless, sweet tasting gas also known as "laughing gas".

N₂O - Dinitrogen monoxide OR Dinitrogen (I) oxide.

(b) NO; NO is a colorless gas.

NO - Nitrogen monoxide OR Nitrogen (II) oxide.

(c) NO2; It is properly written as NO₂

NO₂ is a reddish-brown gas.

NO₂ - Nitrogen dioxide or Nitrogen (IV) oxide.

(d) N2O5; It is properly written as N₂O₅

N₂O₅ is a white solid.

N₂O₅ - Dinitrogen pentoxide.

(e) N2O4; It is properly written as N₂O₄;

N₂O₄ is a red-brown liquid with an unpleasant smell.

N₂O₄ - Dinitrogen tetraoxide.

6 0
4 years ago
How many grams of ZnO would you need to produce 50 g of ZnCl2? (The atomic mass of Zn is 65.38 and of Cl is 35.45.) ZnO(s) + 2HC
marta [7]

.37 grams of ZnO

hope this helps!

4 0
3 years ago
Help please I need it bad
natta225 [31]
= 9.1 × 10^6
(scientific notation)

= 9.1e6
(scientific e notation)

= 9.1 × 10^6
(engineering notation)
(million; prefix mega- (M))

= 9100000
<span>(real number)</span>
5 0
3 years ago
What is a rise in seawater levels pushed to shore during a hurricane called?
zalisa [80]

Answer:

A storm surge

Explanation:

A rise in sea level that happens during tropical cyclones, and storms like typhoons or hurricanes is called a Storm Surge.

5 0
4 years ago
A cylindrical specimen of some metal alloy having an elastic modulus of 126 GPa and an original cross-sectional diameter of 3.4
Delvig [45]

Answer:

The maximum length of the specimen before deformation is 240.64 mm

Explanation:

Strain = stress ÷ elastic modulus

stress = load ÷ area

load = 2130 N

diameter = 3.4 mm = 3.4×10^-3 m

area = πd^2/4 = 3.142 × (3.4×10^-3)^2/4 = 9.08038×10^-6 m^2

stress = 2130 N ÷ 9.08038×10^-6 m^2 = 2.35×10^8 N/m^2

elastic modulus = 126 GPa = 126×10^9 Pa

Strain = 2.35×10^8 ÷ 126×10^9 = 0.00187

Length = extension ÷ strain = 0.45 mm ÷ 0.00187 = 240.64 mm

5 0
3 years ago
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