When two gases or two liquids form a solution, the substance that is present in the largest amount is the?

Select the correct answer. which substance in this redox reaction is the oxidizing agent? cu 2agno3 → 2ag cu(no3)2 a. n b. agno3

lana66690 [7]

AgNO₃ will act as the oxidising agent.

<h3><u>For the given chemical equation:</u></h3>

Cu + 2AgNO₃ → 2Ag + Cu(NO₃)₂

Half reactions for the given chemical reaction:

<u>Reducing agent:</u>

Cu → Cu²⁺ + 2e⁻

Copper is a reducing agent because it is losing 2 electrons, which causes an oxidation process.

<u>Oxidising Agent</u>:

Ag⁺ + e⁻ → Ag

The silver ion undergoes a reduction process and is regarded as an oxidizing agent since it is acquiring one electron per atom.

Hence, AgNO₃ is considered as an oxidizing agent and therefore the correct answer is Option B.

<h3><u>Oxidising and Reducing agents</u></h3>

An oxidizing agent is a substance that reduces itself after oxidizing another material. It passes through a reduction process in which it obtains electrons and the substance's oxidation state is decreased.
A reducing agent is a chemical that oxidizes after reducing another material. It passes through an oxidation process in which it loses electrons and the substance's oxidation state increases.

To know more about the process of Oxidation and Reduction, refer to:

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8 0

11 months ago

Write the number 345 in scientific notation, with the same number of significant figures:

uranmaximum [27]

Answer:

3.45 x 10^2

Explanation:

345= 3 SF

3.45 x 10^2= 3 SF

8 0

3 years ago

A chemist designs a galvanic cell that uses these two half-reactions: half-reaction standard reduction potential (s)(aq)(aq)(l)

miv72 [106K]

Answer:

Reduction (cathode): Cu²⁺(⁺aq) + 2 e⁻ → Cu(s)

Oxidation (anode): Zn(s) → Zn²⁺(⁺aq) + 2 e⁻

Cu²⁺(⁺aq) + Zn(s) → Cu(s) + Zn²⁺(⁺aq)

E°cell = 1.10 V

Explanation:

<em>The half-reactions are missing, but I will propose some to show you the general procedure and then you can apply it to your equations.</em>

<em>Suppose we have the following half-reactions.</em>

<em />

To identify how to make a spontaneous cell, we need to consider the standard reduction potentials (E°red). The half-reaction with the higher E°red will occur as a reduction (in the cathode), whereas the one with the lower E°red will occur as an oxidation (in the anode).

Reduction (cathode): Cu²⁺(⁺aq) + 2 e⁻ → Cu(s) E°red = 0.34 V

Oxidation (anode): Zn(s) → Zn²⁺(⁺aq) + 2 e⁻ E°red = -0.76 V

To get the overall equation we add both half-reactions.

Cu²⁺(⁺aq) + Zn(s) → Cu(s) + Zn²⁺(⁺aq)

The standard cell potential (E°cell) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.

E°cell = E°red, cat - E°red, an

E°cell = 0.34 V - (-0.76 V) = 1.10 V

Since E°cell > 0, the reaction is spontaneous.

5 0

3 years ago

A chemistry student needs 50.0 g of methyl acetate for an experiment. By consulting the CRC Handbook of Chemistry and Physics, t

slamgirl [31]

Explanation:

As density is defined as the mass of a substance divided by its volume.

Mathematically, Density = $\frac{mass}{volume}$

It is given that mass is 50 g and density is 0.934 $g/cm^{3}$ .

Hence, calculate the volume of methyl acetate as follows.

Density = $\frac{mass}{volume}$

0.934 $g/cm^{3}$ = $\frac{50 g}{volume}$

Volume = $53.53 cm^{3}$

or, = $53.53 ml$ (as 1 $cm^{3}$ = 1 mL)

Thus, we can conclude that the volume of methyl acetate the student should pour out is $53.53 ml$ .

3 0

3 years ago

Explain the difference between heat and temperature. Does 1 L of water at 658°F have more, less, or the same quantity of energy

pogonyaev

The answer is- The energy of 1 L water at temperature 347.78 °C have more energy as 1 L of water at temperature 65°C.

Heat is a type of energy that causes a person's body to feel hot or cold.

While the temperature of an object is a parameter that indicates how hot or cold the object is.

How is the temperature in degree Fahrenheit converted to degree celsius?

To convert the temperature in Fahrenheit to Celsius, subtract 32 and multiply by 5/9.

° $C =( ^0F -32) * \frac{5}{9}$

Now, heat is a form of energy that flows from hotter object to colder object and temperature indicates whether the object is hot or cold by measuring its average kinetic energy.
Now, the given temperature of 1 L water is 658 °F. This temperature in degree celsius is calculated as-

°C $= (658 F-32) *\frac{5}{9} = 347.78 \° C$

Now, higher the temperature, higher is the energy of water. Thus, the energy of 1 L water at 347.78 °C have more energy as 1 L of water at 65°C.

To learn more about heat and temperature, visit:

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3 0

2 years ago