There is 55 neutrons in Cesium-130.
Ammonium hydroxide is considered a weak base because it produces few hydroxide ions in aqueous solution. (Option a)
<h3>Strength of electrolytes</h3>
- Strong electrolytes: are completely ionized in aqueous solution.
- Weak electrolytes: are partially ionized in aqueous solution.
Let's consider the ionization of ammonium hydroxide, which is a weak base.
NH₄OH ⇄ NH₄⁺ + OH⁻
Why is it considered a weak base?
a. it produces few hydroxide ions in aqueous solution. Yes, since it dissociates partially.
b. it produces few hydrogen ions in aqueous solution. No, since it does not produce hydrogen ions.
c. it does not conduct electricity in aqueous solution. No, since it conducts electricity, although poorly.
d. it will not take part in a neutralization reaction. No, since it will be neutralized by acids.
Ammonium hydroxide is considered a weak base because it produces few hydroxide ions in aqueous solution.
Learn more about weak bases here: brainly.com/question/322250
#SPJ1
See the sketch attached.
<h3>Explanation</h3>
The Lewis structure of a molecule describes
- the number of bonds it has,
- the source of electrons in each bond, and
- the position of any lone pairs of electrons.
Atoms are most stable when they have eight or no electrons in their valence shell (or two, in case of hydrogen.)
- Each oxygen atom contains six valence electrons. It demands <em>two</em> extra electrons to be chemically stable.
- Each sulfur atom contains six valence electrons. It demands <em>two </em> extra electrons to be chemically stable.
- Each hydrogen atom demands <em>one</em> extra electron to be stable.
H₂O contains two hydrogen atoms and one oxygen atom. It would take an extra 2 + 2 × 1 = 4 electrons for all its three atoms are stable. Atoms in an H₂O would achieve that need by sharing electrons. It would form a total of 4 / 2 = 2 O-H bonds.
Each O-H bond contains one electron from oxygen and one from hydrogen. Hydrogen has no electron left. Oxygen has six electrons. Two of them have went to the two O-H bonds. The remaining four become 4 / 2 = 2 lone pairs. The lone pairs repel the O-H bonds. By convention, they are placed on top of the two H atoms.
Similarly, atoms in a SO₂ molecule demands an extra 2 × 2 + 2 = 6 electrons for its three atoms to become chemically stable. It would form 6 / 2 = 3 chemical bonds. Loops are unlikely in molecules without carbon. As a result, one of the two O atoms would form two bonds with the S atom while the other form only one.
Atoms are unstable with an odd number of valence electrons. The S atom in SO₂ would have become unstable if it contribute one electron to each of the three bond. It would end up with 3 × 2 + 3 = 9 valence electrons. One possible solution is that it contributes two electrons in one particular bond. One of the three bonds would be a coordinate covalent bond, with both electrons in that bond from the S atom. In some textbooks this type of bonds are also known as dative bonds.
Dots and crosses denotes the origin of electrons in a bond. Use the same symbol for electrons from the same atom. Electrons from the oxygen atoms O are shown in blue in the sketch. They don't have to be colored.
Answer:
True
Explanation:
The desert refers to a region of arid land which is characterized by extreme temperatures, extreme dryness, low amount of precipitation and generally harsh living conditions. Because of these harsh conditions, they have been tagged with various names ranging from 'Death Valley' to 'the place from where there is no return' etc.
Every desert is made up of 2 components: the <u>biotic (living) component</u> and the <u>abiotic (non-living) component</u>. The biotic (living) component consists of the plants and animals that have adapted to these harsh living conditions e.g. Cactus or Cacti, Holly plants, Camels, Lizards, Snakes etc. The abiotic (non-living) component consists of climate (subtropical deserts which are extremely cold or temperate deserts which are extremely hot), location, precipitation/rainfall
Negative force
The woman is applying force to stop the child or to prevent him from running.
I hope this helps...