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2 years ago

What might happen when a gas is exposed to a small flame?

Chemistry

1 answer:

Verizon [17]2 years ago

3 0

Answer:

The fire may grow bigger, depending on the gas.

Explanation:

If you expose more air to a small flame then it could grow larger because air keeps fire alive.

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How are genetic engineering and artificial selection similar?

adelina 88 [10]

Answer:

both genetic engineering and artificial selection allow humans to change a species so that its member are better suited for human needs. artificial selection selects for traits already present in a species, whereas genetic engineering creates new traits.

Explanation:

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2 years ago

What is the purpose of a unit conversion?

Nataly [62]

Unit conversion is very important because the rest of the world other than three contries uses the metric system. So, converting unitsis important in science because it uses the metric system. The metric system aremeasurements like cm, m, l, mL, etc.

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2 years ago

When the cations Na+, K+, Rb+, Cs+ are combined with chloride ion in the gas phase to form ion pairs, which pair formation relea

Gemiola [76]

Answer:

NaCl

Explanation:

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2 years ago

Read 2 more answers

The internal combustion engine takes advantage of the ability of the combustion reaction of gasoline to do _______ and move a pi

grandymaker [24]

The answer is C, work. The reaction of the air/gas mixture being ignited produces energy which moves the piston up and down which turns the crankshaft.

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2 years ago

Calculate the mass, in grams, of Ag2CrO4 that will precipitate when 50.0mL of 0.20M AgNO3 solution is mixed with 40.0mL of 0.10M

Darina [25.2K]

Answer:

1.327 g Ag₂CrO₄

Explanation:

The reaction that takes place is:

2AgNO₃(aq) + K₂CrO₄(aq) → Ag₂CrO₄(s) + 2KNO₃(aq)

First we need to identify the limiting reactant:

We have:

0.20 M * 50.0 mL = 10 mmol of AgNO₃

0.10 M * 40.0 mL = 4 mmol of K₂CrO₄

If 4 mmol of K₂CrO₄ were to react completely, it would require (4*2) 8 mmol of AgNO₃. There's more than 8 mmol of AgNO₃ so AgNO₃ is the excess reactant. That makes K₂CrO₄ the limiting reactant.

Now we calculate the mass of Ag₂CrO₄ formed, using the limiting reactant:

4 mmol K₂CrO₄ * $\frac{1mmolAg_2CrO_4}{1mmolK_2CrO_4} *\frac{331.73mg}{1mmolAg_2CrO_4}$ = 1326.92 mg Ag₂CrO₄

1326.92 mg / 1000 = 1.327 g Ag₂CrO₄

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2 years ago