Answer:
2HCL
Explanation:
Both the elements have 2 so when placing the 2 infront ,it'll distribute/ apply to both
The mass of water is calculated as follows
find the moles of each reagent
that is moles = mass/molar mass
for H2s = 84.7/ 34= 2.485 moles
O2 = 78.4 / 32 = 2.45 moles
since 2 moles of H2S react with 3 moles of O2 therefore 2.45 moles of oxygen will be used up therefore O2 is the limiting reagent and H2S is in excess
2H2S + 3O2 ----->2So2 + 2H2O
by use of mole ratio between O2 and H20 which is 3:2 the moles of H2O is therefore = 2.45 x2/3= 1.63 moles of H2O
mass of H2O = moles x molar mass
= 1.63 g x 18g/mol = 29.4 g
Answer:
The attractive forces between them is very weak
Explanation:
Volume of room = 
= 
Now, according to conversion factor, convert 6,400 mg to micrograms
Since, 1 mg is equal to 1000 microgram.
Therefore, 6,400 mg = 
= 6,400,000 micrograms of acetone.
To calculate concentration of acetone, divide volume and evaporated amount of acetone in micrograms.
Thus,
Concentration of acetone = 
= 39296.5910 microgram per cubic meter or 
Hence, concentration of acetone is equal to 
