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2 years ago

Someone pls help me with this test i was in quorintine and missed a lot and the teacher is still making me take it.

Mathematics

1 answer:

earnstyle [38]2 years ago

3 0

In first question x=8, I’m too lazy to solve the rest

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George said if 2 and 4 are factors of a number, then 8 is a factor of the whole number. is he correct explain

Mamont248 [21]

He is correct and incorrect. 2 and 4 can create factors but they can also be factors of other numbers. So 8 can be a factor of bigger whole numbers and can also have it own smaller factors.

8 0

3 years ago

Write all the factors of 8

iren [92.7K]

1,2,4,8
those are the factors of 8

4 0

3 years ago

A research study uses 800 men under the age of 55. Suppose that 30% carry a marker on the male chromosome that indicates an incr

ss7ja [257]

Answer:

a) There is a 12.11% probability that exactly 1 man has the marker.

b) There is a 85.07% probability that more than 1 has the marker.

Step-by-step explanation:

There are only two possible outcomes: Either the men has the chromosome, or he hasn't. So we use the binomial probability distribution.

Binomial probability

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

In this problem, we have that:

30% carry a marker on the male chromosome that indicates an increased risk for high blood pressure, so $\pi = 0.30$

(a) If 10 men are selected randomly and tested for the marker, what is the probability that exactly 1 man has the marker?

10 men, so $n = 10$

We want to find P(X = 1). So:

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 1) = C_{10,1}.(0.30)^{1}.(0.7)^{9} = 0.1211$

There is a 12.11% probability that exactly 1 man has the marker.

(b) If 10 men are selected randomly and tested for the marker, what is the probability that more than 1 has the marker?

That is $P(X > 1)$

We have that:

$P(X \leq 1) + P(X > 1) = 1$

$P(X > 1) = 1 - P(X \leq 1)$

We also have that:

$P(X \leq 1) = P(X = 0) + P(X = 1)$

$P(X = 0) = C_{10,0}.(0.30)^{0}.(0.7)^{10} = 0.0282$

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0282 + 0.1211 = 0.1493$

Finally

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.1493 = 0.8507$

There is a 85.07% probability that more than 1 has the marker.

3 0

3 years ago

How do I factor 14x^2-7xy-147y^2

Viefleur [7K]

STEP 1

Equation at the end of step

((14 • (x2)) - 7xy) - (3•72y2)

Equation at the end of step 2

((2•7x2) - 7xy) - (3•72y2)

STEP 3

STEP 4

Pulling out like terms

4.1 Pull out like factors :

14x2 - 7xy - 147y2 = 7 • (2x2 - xy - 21y2)

Trying to factor a multi variable polynomial :

4.2 Factoring 2x2 - xy - 21y2

Try to factor this multi-variable trinomial using trial and error

Found a factorization : (2x - 7y)•(x + 3y)

6 0

2 years ago

Distributive Property Practice

babymother [125]

Answer:

1: 12x + 8

2: 21y - 3

3: 15p + 20r

Step-by-step explanation:

6 0

2 years ago