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2 years ago

What value of x makes this equation true?

Mathematics

2 answers:

Pavel [41]2 years ago

8 0

-18n-4n= 58-2
-22n=56
n=56/-22
n=2.55

dlinn [17]2 years ago

5 0

Answer:

I am not sure, but my answer is n= –2,(54).

Step-by-step explanation:

2 − 18n = 4n + 58

–4n − 18n = (–2) + 58

–22n=56 |:(–22)

n= –2,(54)

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Elissa needs 8.5 inches of thread to make a friendship bracelet. What is the maximum number of bracelets she can make with 40 in

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Answer:

Step-by-step explanation:

Elissa uses 8.5 inches of thread per bracelet.

She has 40 inches of thread.

To find the maximum number of bracelets she can make, we need to divide.

40 / 8.5 = 4.70588...

We cannot have an unfinished bracelet, so we have to round down.

She can make 4 bracelets with 40 inches of thread.

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2 years ago

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Given cos(x)=1/2, what is the value of cos(x+pi)?

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Answer:

-1/2

Step-by-step explanation:

cos(x+pi) = -cos(x), so the answer is -1/2.

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2 years ago

Simplify (4n^4 - 3n^2 + n)+ (2n^4 -7n^2 + 9n). Express your answer without factoring.

Pie

Answer:

6n^4-10n^2+10n

Step-by-step explanation:

4 n^4+2n^4-3n^2-7n^2+9n+n

6n^4-10n^2+10n

4 0

2 years ago

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What is the slip of the line 4x-2y=5

Eddi Din [679]

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4 0

3 years ago

What is the length of BC , rounded to the nearest tenth?

Arte-miy333 [17]

Step $1$

In the right triangle ADB

Find the length of the segment AB

Applying the Pythagorean Theorem

$AB^{2} =AD^{2}+BD^{2}$

we have

$AD=5\ units\\BD=12\ units$

substitute the values

$AB^{2}=5^{2}+12^{2}$

$AB^{2}=169$

$AB=13\ units$

Step $2$

In the right triangle ADB

Find the cosine of the angle BAD

we know that

$cos(BAD)=\frac{adjacent\ side }{hypotenuse}=\frac{AD}{AB}=\frac{5}{13}$

Step $3$

In the right triangle ABC

Find the length of the segment AC

we know that

$cos(BAC)=cos (BAD)=\frac{5}{13}$

$cos(BAC)=\frac{adjacent\ side }{hypotenuse}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{13}{AC}$

solve for AC

$AC=(13*13)/5=33.8\ units$

Step $4$

Find the length of the segment DC

we know that

$DC=AC-AD$

we have

$AC=33.8\ units$

$AD=5\ units$

substitute the values

$DC=33.8\ units-5\ units$

$DC=28.8\ units$

Step $5$

Find the length of the segment BC

In the right triangle BDC

Applying the Pythagorean Theorem

$BC^{2} =BD^{2}+DC^{2}$

we have

$BD=12\ units\\DC=28.8\ units$

substitute the values

$BC^{2}=12^{2}+28.8^{2}$

$BC^{2}=973.44$

$BC=31.2\ units$

therefore

the answer is

$BC=31.2\ units$

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3 years ago

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