Ask question

Ask question

All categories

2 years ago

11

A car is traveling at 8 m/s accelerates at 3.1 m/s^2 to reach a final top speed of 56 m/s. How much time will pass before the ca

r reaches its top speed

1 answer:

AlekseyPX2 years ago

3 0

Please find attached photograph for your answer.

Hope it helps.

Do comment if you have any query.

You might be interested in

Ropospheric ozone is produced when air pollutants from automobiles and factories chemically react with sunlight. The ozone that

Katyanochek1 [597]

An increase in global surface temperature

7 0

3 years ago

Read 2 more answers

Where would you expect to have more touch receptors: on the palm of your hand or on the back of your hand? Explain your reasonin

anygoal [31]

Answer:

ive answered this

Explanation:

please check your previose question

6 0

3 years ago

What metric unit would you use to estimate the actual distance between Boston and New York?

yarga [219]

The answer to your question is meters.

7 0

3 years ago

Read 2 more answers

Why do the pipes in a steam-heating system need to be insulated?

qaws [65]

Answer:

1. Increase Efficiency: Insulating the condensate or hot water return lines reduces heat loss from the water returning to the boiler. The hotter the water returning to the boiler is, the quicker it is to convert back to steam, which takes less energy to accomplish.

Explanation:

3 0

2 years ago

A common method to measure thermal conductivity of a biomaterial is to insert a long metallic probe axially into the center of a

tia_tia [17]

Answer:

The thermal conductivity of the biomaterial is approximately 1.571 watts per meter-Celsius.

Explanation:

Let suppose that thermal conduction is uniform and one-dimensional, the conduction heat transfer ( $\dot Q$ ), measured in watts, in the hollow cylinder is:

$\dot Q = \frac{2\cdot k\cdot L}{\ln \left(\frac{D_{o}}{D_{i}} \right)}\cdot (T_{i}-T_{o})$

Where:

$k$ - Thermal conductivity, measured in watts per meter-Celsius.

$L$ - Length of the cylinder, measured in meters.

$D_{i}$ - Inner diameter, measured in meters.

$D_{o}$ - Outer diameter, measured in meters.

$T_{i}$ - Temperature at inner surface, measured in Celsius.

$T_{o}$ - Temperature at outer surface, measured in Celsius.

Now we clear the thermal conductivity in the equation:

$k = \frac{\dot Q}{2\cdot L\cdot (T_{i}-T_{o})}\cdot \ln\left(\frac{D_{o}}{D_{i}} \right)$

If we know that $\dot Q = 40.8\,W$ , $L = 0.6\,m$ , $T_{i} = 50\,^{\circ}C$ , $T_{o} = 20\,^{\circ}C$ , $D_{i} = 0.01\,m$ and $D_{o} = 0.04\,m$ , the thermal conductivity of the biomaterial is:

$k = \left[\frac{40.8\,W}{2\cdot (0.6\,m)\cdot (50\,^{\circ}C-20\,^{\circ}C)}\right]\cdot \ln \left(\frac{0.04\,m}{0.01\,m} \right)$

$k \approx 1.571\,\frac{W}{m\cdot ^{\circ}C}$

The thermal conductivity of the biomaterial is approximately 1.571 watts per meter-Celsius.

8 0

3 years ago