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3 years ago

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A car is traveling at 8 m/s accelerates at 3.1 m/s^2 to reach a final top speed of 56 m/s. How much time will pass before the ca

r reaches its top speed

1 answer:

AlekseyPX3 years ago

3 0

Please find attached photograph for your answer.

Hope it helps.

Do comment if you have any query.

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Calculate the object's velocity as shown on the position-time graph,

Cloud [144]

Answer:

10 m/s

Explanation:

The following data were obtained from the question:

Initial Displacement (d1) = 10 m

Final Displacement (d2) = 60 m

Initial time (t1) = 0 s

Final time (t2) = 5 s

Velocity (v) =.?

Next, we shall determine the change in displacement of the object and likewise the change in time.

This can be obtained as follow:

Initial Displacement (d1) = 10 m

Final Displacement (d2) = 60 m

Change in displacement (Δd) = d2 – d1

Change in displacement (Δd) = 60 – 10

Change in displacement (Δd) = 50 m

Initial time (t1) = 0 s

Final time (t2) = 5 s

Change in time (Δt) = t2 – t1

Change in time (Δt) = 5 – 0

Change in time (Δt) = 5 s

Finally, we shall shall calculate the velocity of the object as illustrated below:

Change in displacement (Δd) = 50 m

Change in time (Δt) = 5 s

Velocity (v) =.?

v = Δd/Δt

v = 50/5

v = 10 m/s

Therefore, the velocity of the object is 10 m/s.

4 0

3 years ago

A person who weighs 69kg rides with an acceleration of +1.45 m/s2. What is the force exerted by the legs on the person's upper b

trapecia [35]

Answer:

The force exerted by the legs on the person's upper body 32.106 N.

Given:

Mass = 69 kg

Acceleration = 1.45 $\frac{m}{s^{2} }$

To find:

Force exerted by legs on the person's upper body = ?

Formula used:

Force = mass × acceleration

Solution:

Mass of legs = $\frac{32}{100}$ mass of body

Mass of legs = 22.08 kg

According to Newton's second law of motion,

Force = mass × acceleration

Force = 22.08 × 1.45

Force = 32.106 N

The force exerted by the legs on the person's upper body 32.106 N.

4 0

4 years ago

Standing on top of a building, Bob tosses a baseball straight up with an initial speed of 15 m/s. It takes 4.0 s for the ball to

r-ruslan [8.4K]

Answer:

48.26 m

Explanation:

time to goes up (till stop for a while in the air - maximum height)

vt = vo + a t

0 = 15 + g . t

0 = 15 + (-9.8) . t

9.8t = 15

t = 1.531 s

so the time left to goes down is

4.0 - 1.531 = 2.469 s

height from the top of building can find it by using

vo =√(2gh)

15 = √(2)(9.8).h

15² = 19.6h

h = 225/19.6 = 11.48 m

so the distance of maximum height to the ground is

t = √(2H/g)

2.469 = √(2H/9.8)

2.469² = 2H/9.8

6.096 = 2H/9.8

2H = 6.096 x 9.8 = 59.74 m

so the vertical distance of the building (or the building height's is)

H - h = 59.74 - 11.48 = 48.26 m

5 0

3 years ago

A car accelerates from rest to 31.8 m/s in 6 sec. What is the<br> acceleration?

Savatey [412]

I think the answer is 5.3

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Cell are the ------- living part of an organism

lana66690 [7]

Answer:

3 smallest

Explanation:

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3 years ago

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